Answer:
1.02 moles of AlCl3
Explanation:
Consider the balanced reaction equation shown below;
2Al(s) + 3CuCl2(aq) -------> 2AlCl3 (aq) + 3Cu(s)
This is the balanced reaction equation for the reaction going on above. Recall that the first step in solving any problem is to accurately put down the chemical reaction equation. This balanced reaction equation always serves a reliable guide in solving the problem at hand.
Given that;
3 moles of CuCl2 yields 2 moles of AlCl3
1.53 moles of CuCl2 yields 1.53 × 2 / 3 =1.02 moles of AlCl3
Answer:
30.83 M
Explanation:
17.03052 re in one mole. So, if you multiply it by 30.83, you will get 535 g of ammonia.
In fact, the detailed answer is 30.827009392549122.
Answer:
the answer is the last option yzxw
Explanation:
ph is stronger the lower
The pKa of formic acid is 3.75. At pH of 5.00, b) [formate] > [formic acid].
Formic acid is a weak acid. Thus, together with its conjugate base (formate) they form a buffer system. We can calculate the pH of a buffer system using Henderson-Hasselbach's equation.
![pH = pKa + log \frac{[formate]}{[formic\ acid]} \\\\5.00 = 3.75 + log \frac{[formate]}{[formic\ acid]}\\\\\frac{[formate]}{[formic\ acid]} = 17.8](https://tex.z-dn.net/?f=pH%20%3D%20pKa%20%2B%20log%20%5Cfrac%7B%5Bformate%5D%7D%7B%5Bformic%5C%20acid%5D%7D%20%5C%5C%5C%5C5.00%20%3D%203.75%20%2B%20log%20%5Cfrac%7B%5Bformate%5D%7D%7B%5Bformic%5C%20acid%5D%7D%5C%5C%5C%5C%5Cfrac%7B%5Bformate%5D%7D%7B%5Bformic%5C%20acid%5D%7D%20%20%3D%2017.8)
As expected, at a pH above the pKa, the concentration of formate is higher than that of the formic acid.
The pKa of formic acid is 3.75. At pH of 5.00, b) [formate] > [formic acid].
Learn more: brainly.com/question/22821585
