"log" standing alone actually means "logarithm to the base 10."
Thus, y = log x <=> y = log x
10
y
Stated another way (inverse functions), x = 10
Answer:

Step-by-step explanation:
we have the expression:

To factor this expression we need to indentify the components that are common in both terms.
At first glance there is nothing in common, but we can notice that 30 and 70 are multiples of 10, that is:

so we can substitute this into the expression:

and now that we have the common term (the number 10) we can factorize it, that is, take out the common term and include a parentheses:

Okay, let me just make this a little clearer. Hopefully, this is what you meant:
A. y - 8 = -4(x + 4)
B. y - 8 = 4(x + 4)
C. y + 8 = 4(x - 4)
D. y + 8 = -4(x - 4)
--
This can also be written as y2 - y1 = m(x2 - x1).
Your M is your slope.
Both A and D have their m as a negative 4. Because you are looking for a positive slope, immediately cancel those answers.
* note that you could have also put them in a more standard form and discovered m which is the x in bx.
Now, you are looking for an equation that contains (4,-8).
Because it is written as y2-y1, your y's are actually points if you were to find another slope or something. This part is a bit hard to explain, but -8 is only found in the y coordinate place in answer B. Your answer would be B. For more explanation on that, there's this great site called coolmath.com and if you search for finding the equation of two points, it explains it much better on there, but I would not want to plagiarize.
The answer is B.
Answer:
TC (A) = 40x , TC (B) = 500 + 20x
Step-by-step explanation:
Let the number of students be = x
Hall A Total Cost
Relationship Equation, where TC (A) = f (students) = f (x) 40 per person (student) = 40x
Hall B Total Cost
Relationship Equation, where TC (B) = f (students) = f (x) 500 fix fee & 20 per person (student) = 500 + 20x
Answer:
8y^3 + 6y^2 - 29y + 15
Step-by-step explanation:
8y^3 + 12y^2 - 20y - 6y^2 - 9y + 15
then
8y^3 + 6y^2 - 29y + 15 is the product
Best regards