A hollow ball weighs 40 newtons. In a water tank, it displaces 15 newtons of water. What is the buoyant force on the ball? Will
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Answer:
F = 96.11 N
friction force =33.48 N
Explanation:
given,
mass of block M = 7.50 kg
acceleration = 3 m/s²
µ s = 0.443 and µ k = 0.312
angle with the horizontal = 25°
the component of force along the incline is F cos theta
normal reaction ,
N = 66.68+ .423 F
for the mass
0.906 F - 0.132 F - 31.09 - 20.8 = 22.5
0.774F = 74.39
F = 96.11 N
normal force ,
N = 66.68 + .423×96.11
=107.33 N
friction force = .312 × N
= 0.312× 107.33
friction force =33.48 N