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2 years ago

Determine the solution you would get for 4=8

Mathematics

2 answers:

My name is Ann [436]2 years ago

8 0

Answer:

C. no solution

Step-by-step explanation:

N76 [4]2 years ago

6 0

The answer is no solution (:

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Perimeters and Areas of Rectangles (PLEASE HELP)

Lynna [10]

Answer:

i will only answer 11 and 4

Step-by-step explanation:

4: 23 i know its not the whole thing

11:45 its not the full thing

6 0

2 years ago

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Solve this equation for x x-2y=8

nignag [31]

Im pretty sure the answer is x=-2

8 0

3 years ago

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The state of Texas gained its independence from

padilas [110]

It would be 2020-1836 = 184 years ago

3 0

3 years ago

there are 15 people in a book club. ten people read for an average of 65 minutes each day. The remaining people read for an aver

serg [7]

Average of 10 people = 65

65 × 10 = 650

average of 5 people = 35

35 × 5 = 175

650 + 175 = 825

825 ÷ 15 = 55

the average reading time for the entire book club each day is 55 minutes a day

8 0

3 years ago

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Find the indefinite integral. (Use C for the constant of integration.)

mart [117]

Answer:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C$

tep-by-step explanation:

In order to find the integral:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx$

we can do the following substitution:

Let's call

$u=(x^3-x^2+x)$

Then

$du = (3x^2-2x+1) dx$

which allows us to do convert the original integral into a much simpler one of easy solution:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \int\ {u^7 \, du = \frac{1}{8} \,u^8 +C$

Therefore, our integral written in terms of "x" would be:

$\int\ {(3x^2-2x+1)\,(x^3-x^2+x)^7} \, dx = \frac{1}{8} (x^3-x^2+x)^8+C$

7 0

3 years ago