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BaLLatris [955]

2 years ago

11

HELP ME: Lee works at a job where her pay varies directly with the number of hours she works. Her pay for 6.5 hours is $49.40. W

rite a direct variation equation relating Lee’s pay x to the hours worked y. Then find her pay if she works 25 hours in a week. y = 7.6x; $190

1 answer:

Alex_Xolod [135]2 years ago

3 0

Answer: 90$

Step-by-step explanation:

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Mary had a back surgery and was given a prescription with instructions to take 4 tablets twice a day for pain. How many tablets

astraxan [27]

Answer:

14 tablets

Step-by-step explanation:

In one day 2 tablets and in 7 day

7×2=14 tablets

4 0

3 years ago

A number is 6 greater than 1\2 another number. If the sum of the numbers is 21,find the numbers.

Lemur [1.5K]

Let 1 number equal x
<span>Let the other number equal 1/2x + 6

x + (1/2x + 6) =21
1 & 1/2 x + 6 =21
1 & 1/2 x =15
</span>

5 0

3 years ago

A computer manufacturer shipped a total of 50 machines to its two warehouses, one in west and one in east. It cost 20$ per machi

Natalka [10]

E + w = 50.....w = 50 - e
25e + 20w = 1090

25e + 20(50 - e) = 1090
25e + 1000 - 20e = 1090
25e - 20e = 1090 - 1000
5e = 90
e = 90/5
e = 18 <=== the east got 18

w = 50 - e
w = 50 - 18
w = 32 <=== the west got 32

5 0

3 years ago

Read 2 more answers

6+2x+4(x+5) <br><br> Pleaseee♥️♥️♥️ B

inessss [21]

The answer is: 6x+26 ||

8 0

3 years ago

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Find the exact value of cot(15degrees) using half angle formulas?

liubo4ka [24]

Double angle (or half angle, depending how you look at it) identities:

$\cos^2\dfrac x2=\dfrac{1+\cos x}2$

$\sin^2\dfrac x2=\dfrac{1-\cos x}2$

$\implies\cot^2\dfrac x2=\dfrac{\cos^2\frac x2}{\sin^2\frac x2}=\dfrac{1+\cos x}{1-\cos x}$

So we have

$\cot^215^\circ=\dfrac{1+\cos30^\circ}{1-\cos30^\circ}=\dfrac{1+\frac{\sqrt3}2}{1-\frac{\sqrt3}2}$

$\implies\cot^215^\circ=7+4\sqrt3$

$\implies\cot15^\circ=\sqrt{7+4\sqrt3}=2+\sqrt3$

Note that when taking the square root, we should take into account that that could yield two possible solutions, but we know $\cos15^\circ>0$ and $\sin15^\circ>0$ , so it's also the case that $\cot15^\circ>0$ .

Also, the reason we have equality in the last step can be explained like so:

$7+4\sqrt3=4+4\sqrt3+3=4+4\sqrt3+(\sqrt3)^2=(2+\sqrt3)^2$

(not unlike the process used to complete the square)

8 0

3 years ago

Read 2 more answers