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vivado [14]
2 years ago
12

3 questions I WILL MARK BRAINLYEST 100 POINTS!!!!!!

Physics
1 answer:
sammy [17]2 years ago
5 0

Answer:

19 on the first one

Explanation:

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How long will it take you to travel 20 miles on a bus that drives 60 miles/h?
ValentinkaMS [17]

Answer:

<u>20 Minutes</u>

<u></u>

Explanation:

Well we know Mph (Miles per hour) is distance over time : \frac{distance}{time} \\

R (rate) = 60

d (distance) = 20

t (time) = Unknown

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 R = \frac{d}{t}  

   ↓

60 = \frac{20}{t}

   ↓

 t = \frac{20}{60}

    ↓

 t = \frac{1}{3}  or 0.3333

<em>So basically it would take one third of an hour. Lets change these units to minutes.</em>

60 * 0.333333 = 20

<em>So it would take you </em><u><em>20 minutes</em></u><em> to drive 20 miles on a bus that drives 60 mph</em>

<em />

Hope that helps

<em>~Siascon~</em>

8 0
3 years ago
Which of the following is not a synthesis reaction?
Nastasia [14]
C is the awnser because c is single replacement
6 0
3 years ago
Describe the motion of an unanchored rowboat when a water wave passes
USPshnik [31]
It mimics the movement of the waves 
6 0
3 years ago
Read 2 more answers
Write the energy conversion when climbing a ladder​
Volgvan
A child climbing a ladder is transforming kinetic energy into potential energy.
7 0
3 years ago
Part complete How long must a simple pendulum be if it is to make exactly one swing per five seconds?
shtirl [24]

Answer:

L=6.21m

Explanation:

For the simple pendulum problem we need to remember that:

\frac{d^{2}\theta}{dt^{2}}+\frac{g}{L}sin(\theta)=0,

where \theta is the angular position, t is time, g is the gravity, and L is the length of the pendulum. We also need to remember that there is a relationship between the angular frequency and the length of the pendulum:

\omega^{2}=\frac{g}{L},

where \omega is the angular frequency.

There is also an equation that relates the oscillation period and the angular frequeny:

\omega=\frac{2\pi}{T},

where T is the oscillation period. Now, we can easily solve for L:

(\frac{2\pi}{T})^{2}=\frac{g}{L}\\\\L=g(\frac{T}{2\pi})^{2}\\\\L=9.8(\frac{5}{2\pi})^{2}\\\\L=6.21m

3 0
3 years ago
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