Answer:
The displacement is 386.16m
Explanation:
A seal dives to a depth of 248m. To find displacement, we must calculate the resultant vectors which will give us the displacement
R= sqrt(vector1+vector2)
Since this is a right angle triangle
R= sqrt(248^2 + 296^2)
R= sqrt(149120)
R= 386.16m
Displacement = 386.16m
Answer:
The horizontal component of her velocity is approximately 1.389 m/s
The vertical component of her velocity is approximately 7.878 m/s
Explanation:
The given question parameters are;
The initial velocity with which Margaret leaps, v = 8.0 m/s
The angle to the horizontal with which she jumps, θ = 80° to the horizontal
The horizontal component of her velocity, vₓ = v × cos(θ)
∴ vₓ = 8.0 × cos(80°) ≈ 1.389
The horizontal component of her velocity, vₓ ≈ 1.389 m/s
The vertical component of her velocity,
= v × sin(θ)
∴
= 8.0 × sin(80°) ≈ 7.878
The vertical component of her velocity,
≈ 7.878 m/s.
Explanation:
a. The velocity of the wind as a vector in component form will be represented as v vector:

b.The velocity of the jet relative to the air as a vector in component form will be represented as u vector

c. The true velocity of the jet as a vector will be represented as w:


d. The true speed of the jet will be calculated as:




e. The direction of the jet will be:



Longitude- Horizontal (East West)
Latitude- Vertical (North South)
There are two atoms of potassium bonded to one atom of sulfur.