225 = 1/2 (50) (v2)
225 = 25 (v2)
225/25 = v2
9 = v2
√9 = v
v = 3 m/s
Answer:
so here it will move in circle with radius 4.06 cm
Explanation:
As we know that proton is moving towards west while the magnetic field is vertically upwards
So here the force on the proton must be perpendicular to the velocity
So here we have

so here we have

since force is perpendicular to the velocity so here it must be centripetal force
here we have

so we have



so here it will move in circle with radius 4.06 cm
Answer: Black hole.
Explanation:
As the massive star "compacts" under its own gravity, it triggers a massive supernova, after this point the remains of the star can become a neutron star, which is a very compact star made primarily, as the name says, of neutrons. The other possibility is a black hole, which is a finite region of space wherein it's interior there is a big concentration of mass, which creates a gravitational field strong enough that there is no particle that can escape it.
The answer to your question is C
Because it goes from point A to point C to make one wavelenght