Answer:
(a) θ1 = 942.5rad, (b) θ2 = 13195 rad
Explanation:
(a) Given
ωo = 0 rad/s
ω = 3600rev/min = 3600×2(pi)/60 rad/s
ω = 377rad/s
t1 = 5s
θ1 = (ω + ωo)t/2
θ1 = (377 +0)×5/2
θ1 = 942.5 rads
(b) ωo = 377rad/s
ω = 0 rad/s
t2 = 70s
θ2 = (ω + ωo)t/2
θ2 = (377 +0)×70/2
θ2 = 13195 rad
<span>10 hertz
Hertz is the frequency of oscillation which is the number of oscillations per second. So if something takes 0.10 s per oscillation, divide 1 second by the period to get the frequency. So
1 / 0.10s = 10 1/s = 10 Hertz
Therefore the object is vibrating at 10 hertz.</span>
Answer:
Closed system, because the speed of the car is as expected in the case where an object has uniform acceleration for a time t
Explanation:
Here in the question it is mentioned that a toy car has an initial acceleration of 2m/s² across a horizontal surface so we can say that it is acted upon by an external force
Assuming that the acceleration is constant and the reason for this assumption is there at the last
The major difference between an open system and closed system is in case of open system there will be transfer of matter and in case of closed system there will be no change in matter of the system
If acceleration is constant in case of closed system we can expect the speed of the car after a time t by using the formula
s = u×t + 0·5×a×t²
where s is the distance travelled
t is the time taken to travel that distance
u is the initial velocity
a is the acceleration of that system
But in case of open system as there will be a change of mass there will be a change in velocity of the system so in this case we cannot expect the speed of the car after a time t
And if the acceleration is not constant then we cannot say that the toy car is an open system or closed system, that is why we are assuming that the acceleration of the toy car is constant
Acceleration is given by change in velocity divided by change in time, so his acceleration should just be (10-5)/5 which is [tex] \frac{5}{2} \frac{m}{s^{2}} [tex]
The driveway is 40 meters plus 225/4. You can do the math.
