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2 years ago

5

Brlan is repairing an old alarm clock. He needs to replace a device that converts the electric energy into sound energy. Which o

f these devices
should he use?
OA.
O B.
C.
battery
buzzer
motor
Switch

1 answer:

Brums [2.3K]2 years ago

3 0

The answer is buzzer

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What is the only possible value of ml for an electron in an s orbital?

Archy [21]

Answer:

zero

Explanation:

$m_l$ is the magnetic quantum number.

The only possible value for the magnetic quantum number for an electron in an s orbital is 0.

The first three quantun numbers are:

n: principal quantum number. It may have positive integer values: 1, 2, 3, 4,5, 6, 7, ...

$l$ : Azimuthal or angular momentum quantum number. It may have integer values from 0 to n - 1.

This quantum number is related to the type (or shape) of the orbital:

For s orbitals $l=0$

For p orbitals $l=1$

For d orbitals $l=2$

For f orbitals $l=3$

In this case, it is an s orbital, so we have $l=0$ .

$m_l$ , the third quantum number can have integer values ${from-l}$ to ${+l}$

Since, for the s orbitals $l=0$ , the only possible value for ${m_l}$ is zero.

4 0

3 years ago

Scott travels north 5 miles, then goes west 3 miles, and then goes south for 2 miles.

Yuki888 [10]

Scott traveled 10 miles

5 0

2 years ago

M (b) Calculate the speed of an electron that is accelerated through the same electric potential difference.

MaRussiya [10]

The speed of a electron that is accelerated from rest through an electric potential difference of 120 V is $6.49\times10^6m/s$

<h3>How to calculate the speed of the electron?</h3>

We know, that the energy of the system is always conserved.

Using the Law of Conservation of energy,

$\triangle K+\triangle$ U=0

Here, K is the kinetic energy and U is the potential energy.

Now, substituting the formula of U and K, we get:

$(\frac{1}{2} mv^2)+(-q\triangle V)$ =0------(1)

Here,

m is the mass of the electron

v is the speed of the electron

q is the charge on the electron

V is the potential difference

Let $v_f$ and $v_i$ represent the final and initial speed.

Here, $v_i$ =0

Solving for $v_f$ , we get:

$v_f=\sqrt{\frac{-2q\triangle V}{m} }$

$=\sqrt{\frac{2\times1.602\times10^{-19}\times 120}{9.109\times10^{-31}} }$

=6.49 $\times10^6$ m/s

To learn more about the conservation of energy, refer to:

brainly.com/question/2137260

#SPJ4

4 0

1 year ago

Find the net work W done on the particle by the external forces during the motion of the particle in terms of the initial and fi

steposvetlana [31]

Answer:

$W=K_f-K_i$

Explanation:

The work done on a particle by external forces is defined as:

$W=\int\limits^{r_f}_{r_i} {F\cdot dr} \,$

According to Newton's second law $F=ma$ . Thus:

$W=\int\limits^{r_f}_{r_i}{ma\cdot dr} \,\\$

Acceleration is defined as the derivative of the speed with respect to time:

$W=m\int\limits^{r_f}_{r_i}{\frac{dv}{dt}\cdot dr} \,\\\\W=m\int\limits^{r_f}_{r_i}{dv \cdot \frac{dr}{dt}} \,$

Speed is defined as the derivative of the position with respect to time:

$W=m\int\limits^{v_f}_{v_i} v \cdot dv \,$

Kinetic energy is defined as $K=\frac{mv^2}{2}$ :

$W=m\frac{v_f^2}{2}-m\frac{v_i^2}{2}\\W=K_f-K_i$

3 0

2 years ago

Acceleration is generally defined as the time rate of change of velocity. When can it be defined as the time rate of change of s

Lena [83]

Answer:

When the velocity doesn't change its direction

Explanation:

Since velocity vector has 2 components: direction and magnitude, and speed is the velocity's magnitude. So if the velocity doesn't change its direction, we essentially use its magnitude, aka speed, to calculate the rate of change for acceleration.

8 0

3 years ago

Read 2 more answers