Answer:
q₃=5.3nC
Explanation:
First, we have to calculate the force exerted by the charges q₁ and q₂. To do this, we use the Coulomb's Law:
Since we know the net force, we can use this to calculate q₃. As q₁ is at the right side of q₃ and q₁ and q₃ have opposite signs, the force F₁₃ points to the right. In a similar way, as q₂ is at the left side of q₃, and q₂ and q₃ have equal signs, the force F₂₃ points to the right. That means that the resultant net force is the sum of these two forces:
In words, the value of q₃ must be 5.3nC.
Answer:
<em>The cyclist is traveling at 130 m/s</em>
Explanation:
<u>Constant Acceleration Motion
</u>
It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.
Being a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:
The cyclist initially travels at 10 /s and it's accelerating at a=6m/s^2. We need to know the new speed when t= 20 seconds have passed.
Apply the above equation:
The cyclist is traveling at 130 m/s
Answer:
Explanation:
The angular momentum of electron mvR = 6 x 10⁻²⁵ Js
Magnetic field B = 2.5 x 10⁻³ T
radius of circular path R = mv / Bq
where m is mass , v is velocity and q is charge on electron
R² = mvR / Bq
R² = 6 x 10⁻²⁵ / 2.5 x 10⁻³ x 1.6 x 10⁻¹⁹
= 1.5 x 10⁻³
R = 3.87 x 10⁻² m
mvR = 6 x 10⁻²⁵
v = 6 x 10⁻²⁵ / mR
= 6 x 10⁻²⁵ / 9.1 x 10⁻³¹ x 3.87 x 10⁻²
= .17 x 10⁸
= 17 x 10⁶ m/s
West to east.
The earth is spinning on its own axis. Thus, the area of the equator directly hit by the sun's heat and more solar radiation compared to any other area. That same heat warmth the atmosphere. Warm air rises towards the pole which is cooler. This is the reason of constant movement of the atmosphere.
The Coriolis force governed the air flows towards the pole. While the earth is spinning plus the movement of air north or south, the air follows a <span>curved path, toward the east.</span>