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Yuri [45]
3 years ago
8

Keisha drew a diagram to compare two of the fundamental forces. A venn diagram of 2 intersecting circles with the left circle la

beled weak nuclear force and the right circle labeled strong nuclear force. There is an X in the weak nuclear force circle. There is a Z in the strong nuclear force circle. There is a Y in the intersecting area. Which labels belong in the areas marked X, Y, and Z? X: Always attractive Y: Very small range Z: Attractive and repulsive X: Attractive and repulsive Y: Very small range Z: Always attractive X: Very small range Y: Attractive or repulsive Z: Infinite range X: Infinite range Y: Attractive or repulsive Z: Very small range
Physics
1 answer:
slamgirl [31]3 years ago
8 0

Answer: B)

X: Attractive and repulsive

Y: Very small range

Z: Always attractive

I just took the test :)

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Viefleur [7K]
Genius right dear friend

8 0
3 years ago
The following chart provides the pH of some common foods. How many would be considered basic?
Yuri [45]

The ones with pH greater than 7

Explanation:

A pH scale is a scale for expressing the level of acidity or alkalinity of aqueous solutions.

This scale is called a pH or pOH scale. The pH is the common one.

pH of a solution is the negative logarithm to base 10 o the hydrogen ion concentration of the solution.

  • The scale ranges from 1 through 14.
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learn more:

acidity brainly.com/question/5121777

#learnwithBrainly

6 0
3 years ago
The most soaring vocal melody is in Johann Sebastian Bach's Mass in B minor. In one section, the basses, tenors, altos, and sopr
OlgaM077 [116]

Answer:

Detailed step wise solution is attached below

Explanation:

(a) wavelength of the initial note 2.34 meters

(b) wavelength of the final note 0.389 meters

(d) pressure amplitude of the final note 0.09 Pa

(e) displacement amplitude of the initial note 4.78*10^(-7) meters

(f) displacement amplitude of the final note 3.95*10^(-8) meters

6 0
3 years ago
What is a net force on an object that has a mass of 20.0 kg, an applied force of 100 n moving on a surface with a friction coeff
sergiy2304 [10]

The net force on the object as described is; 58.84N

Two forces acting on the object are;

  • The <em>applied force and the frictional force.</em>

In essence; the frictional force can be evaluated as;

  • Frictional force; = coefficient × Weight of object.

  • Frictional force = 0.21 × 20 × 9.8.

  • Frictional force = 41.16N

  • The Net force = Applied force - frictional force

  • Net force = 100 - 41.16N

Net Force = 58.84 N.

Read more:

brainly.com/question/94428

5 0
2 years ago
You plan to take a trip to the moon. Since you do not have a traditional spaceship with rockets, you will need to leave the eart
hichkok12 [17]

Answer:

v = 3.5 \times 10^5 m/s

Explanation:

At some distance from the Earth the force of attraction due to moon is balanced by the force due to Moon

so we will have

\frac{GM_em}{r^2} = \frac{GM_m}{(d-r)^2}

now we have

\frac{d - r}{r} = \sqrt{\frac{M_m}{M_e}}

\frac{3.844\times 10^8 - r}{r} = \sqrt{\frac{7.36 \times 10^{22}}{5.9742\times 10^{24}}}

so we will have

r = 3.46 \times 10^8 m

Now by energy conservation

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-6.26 \times 10^{8} - 13046 + \frac{1}{2}v^2 = -1.15 \times 10^6 - 1.28 \times 10^5

v = 3.5 \times 10^5 m/s

7 0
3 years ago
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