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vlada-n [284]
2 years ago
12

In order to change a 2.15 kg handcart's velocity from 1.2 m/s

Physics
1 answer:
photoshop1234 [79]2 years ago
7 0

Answer: E 1.29 N•s

Explanation: math

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How much work is done lifting a 9.10-kg box straight up onto a shelf that is 1.80 m high
love history [14]

P= 10m = 10 x 9.10 = 91 N

Work is done lifting a 9.10-kg box straight up onto a shelf that is 1.80 m high :

A= Ph = 91 x 1.80 = 163.8 J

ok done. Thank to me :>

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A ______ is a network that has all connected devices located in the same physical location.
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3 years ago
A man standing on a bus remains still when the bus is at rest. When the bus moves forward and then slows down the man continues
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Which of the following are examples of energy being conserved? Choose all that apply A light bulb constantly changes electrical
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Read 2 more answers
Cesium-137 undergoes beta decay and has a half-life of 30.0 years. How many beta particles are emitted by a 14.0-g sample of ces
Mandarinka [93]

Answer: 0.81\times 10^{16} beta particles

Explanation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass = 14.0 g

Molar mass = 137 g/mol

\text{Number of moles of cesium}=\frac{14.0g}{137g/mol}=0.102moles

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 mole of cesium contains atoms =  6.023\times 10^{23}

0.102 moles of cesium contains atoms =  \frac{6.023\times 10^{23}}{1}\times 0.102=0.614\times 10^{23}

The relation of atoms with time for radioactivbe decay is:

N_t=N_0\times \frac{1}{2}^{\frac{t}{t_{\frac{1}{2}}}}

Where N_t =atoms left undecayed

N_0 = initial atoms

t = time taken for decay = 3 minutes

{t_{\frac{1}{2}}} = half life = 30.0 years = 1.577\times 10^7 minutes

The fraction that decays  :  1-(\frac{1}{2})^{\frac{3}{1.577\times 10^7}}=1.32\times 10^{-7}

Amount of particles that decay is  = 0.614\times 10^{23}\times 1.32\times 10^{-7}=0.81\times 10^{16}

Thus 0.81\times 10^{16} beta particles are emitted by a 14.0-g sample of cesium-137 in three minutes.

7 0
3 years ago
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