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RoseWind [281]
3 years ago
15

An automobile is traveling on a long, straight highway at a steady 76.0 mi/h when the driver sees a wreck 180 m ahead. at that i

nstant, she applies the brakes (ignore reaction time). between her and the wreck are two different surfaces. first there is 130 m of ice, where the deceleration is only 1.20 m/s2 . from then on, it is dry concrete, where the deceleration is a more normal 7.10 m/s2 .
Physics
1 answer:
masha68 [24]3 years ago
3 0

a) The car’s speed just after leaving the icy portion of the road is the first part

We have s = ut +\frac{1}{2} at^2

Here s = 130 m, a = -1.2 m/s^2, u = 76 mile/hr = 33.975 m/s

             130 = 0*t - 0.5*(-1.2)*t^2\\ \\ \\ t=14.72 seconds

After 14.72 seconds cars speed is given by v =u +at

                                                          u = 33.975m/s, a = -1.2 m/s^2

                                                      v = 33.975-1.2*14.72 = 16.31 m/s

   So velocity of car on leaving icy surface = 16.31 m/s

b) Time taken after icy surface

              0 = 16.31 - 7.10*t

              t = 2.23 seconds

         Distance traveled during this time

                   v^2 = u^2+2as\\ \\ 0 = 16.31^2 - 2*7.10*s\\ \\ s = 18.74 m

   Total distance traveled = 130+18.74 = 148.74 m

c) Total time taken = 14.72+2.23=16.95 seconds

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When a firecracker explodes, what types of energy does it give off?
fomenos
The answer is c. 
Sound, light and heat energy.

Hope this helped :)
7 0
3 years ago
Si la fuerza de repulsión entre dos cargas es 18 × 1013
sattari [20]

Answer:

Explanation:

F = kQq/r²

r = √(kQq/F)

a)  r = √(8.899(10⁹)(8)(4) / 18(10¹³)) = 0.0397749... m

  r = 40 mm

b) r = √(8.899(10⁹)(12)(3) / 18(10¹³)) = 0.0421876... m

   r = 42 mm

5 0
3 years ago
Dont know whether its b or c. (cuz for sure it transports energy)
masha68 [24]

Sound waves are a type of classical waves and so they transport only energy without transporting matter through the medium.

6 0
3 years ago
A positively charged particle initially at rest on the ground accelerated upward to 100m/s in 2.00s. If the particle has a charg
VashaNatasha [74]

Answer:

Explanation:

From the question we are told that

     The initial velocity is  u  =  100 m/s

       The time taken is  t = 2.0 s

       The charge to mass ratio is  Q/m  =  0.100 C/kg

       

Generally the acceleration is mathematically evaluated as

              a  =   \frac{u}{t }

substituting values  

               a =   \frac{100}{2}

                a =  50 \ m/s^2

The electric field is mathematical represented as

             E = \frac{(a+g)}{Q/m}

substituting values

              E = \frac{(50+9.8)}{0.100}

              E = 598 \ N/C

4 0
3 years ago
The force F acting on a particle constrained to move along the x - axis is given by the fucntion F ( x ) = a x ( b − c x 2 ) [ a
arlik [135]

Answer:

The equilibrium points include

x₁ = - 1.177

x₂ = 0

x₃ = 1.177

Explanation:

At equilibrium, the sum of forces acting on a body is equal to zero.

F(x) = ax (b − cx²) [a = 8.97, b = 7.83, c = 5.65]

F(x) = (abx - acx³)

= (8.97×7.83)x - (8.97×5.65)x³

F(x) = 70.2351x - 50.6805x³

At equilibrium, F(x) = 0

70.2351x - 50.6805x³ = 0

x(70.2351 - 50.6805x²) = 0

x = 0 or (70.2351 - 50.6805x²) = 0

70.2351 - 50.6805x² = 0

50.6805x² = 70.2351

x² = (70.2351/50.6805)

x² = 1.385840708

x = ± 1.177

So, x = -1.177, 0 and 1.177

x₁ = - 1.177

x₂ = 0

x₃ = 1.177

Hope this Helps!!!

6 0
3 years ago
Read 2 more answers
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