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2 years ago

X Angle 1 and Angle 2 are supplementary, Solve for x if angle 1 = 2x -3 and/3

Mathematics

1 answer:

Alona [7]2 years ago

5 0

9514 1404 393

Answer:

∠1 = 67°; ∠2 = 113°

Step-by-step explanation:

Given:

∠1 = 2x-3

∠2 = 3x +8

∠1 +∠2 = 180

Find:

∠1, ∠2

Solution:

Substituting the first two relations into the third, we have ...

(2x -3) +(3x +8) = 180

5x +5 = 180 . . . eliminate parentheses

x + 1 = 36 . . . . . divide by 5

x = 35

Then the angles are ...

∠1 = 2x-3 = 2(35) -3

∠1 = 67°

∠2 = 3x +8 = 3(35) +8

∠2 = 113°

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Car rentals involve a $130 flat fee and an additional cost of $31.67 a day what is the maximum number of days you can rent a car

Dmitry_Shevchenko [17]

The equation is $130 + $31.67x = 500
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Divide $31.67 from both sides
X=11.68
BUT
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8 0

3 years ago

Read 2 more answers

Write the cubic polynomial function f(x)in expanded form with zeros −6,−5,and −1, given that f(0)=60

RSB [31]

Answer:

$f(x)=2x^{3}+24x^{2}+82x+60$

Step-by-step explanation:

we know that

The roots of the polynomial are the values of x when the value of the polynomial f(x) is equal to zero

The roots of the polynomial function are

x=-6 -----> (x+6)=0

x=-5 -----> (x+5)=0

x=-1 -----> (x+1)=0

The equation of the cubic polynomial is

$f(x)=a(x+6)(x+5)(x+1)$

where

a is the leading coefficient

Remember that

f(0)=60

That means ------> For x=0 the value of f(x) is equal to 60

substitute the value of x and the value of y in the function and solve for a

$60=a(0+6)(0+5)(0+1)$

$60=a(6)(5)(1)$

$60=30a$

$a=2$

$f(x)=2(x+6)(x+5)(x+1)$

Applying the distributive property

Convert to expanded form

$f(x)=2(x+6)(x+5)(x+1)\\\\f(x)=2(x+6)(x^{2}+x+5x+5)\\\\f(x)=2(x+6)(x^{2}+6x+5)\\\\f(x)=2(x^{3}+6x^{2}+5x+6x^{2}+36x+30)\\\\f(x)=2x^{3}+24x^{2}+82x+60$