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velikii [3]
3 years ago
6

IN which of the following conditions would a person not hear an echo? A. A sound wave reaches the ear, and the reflected wave re

aches the ear less than 0.1 seconds later, B. A person is standing in the range of the sound waves coming from the original sound sources as well as the reflected waves, C. The reflecting wave source is approximately 21.5 meters from the person, D. a person is standing 30 meters in front of the reflecting surface.
Physics
2 answers:
GenaCL600 [577]3 years ago
7 0

Answer:

A. A sound wave reaches the ear, and the reflected wave reaches the ear less than 0.1 seconds later,

Explanation:

Human hear can not differentiate two successive sounds when the period between the sounds is less than 0.1 seconds.When the distance between the source of sound and the reflecting surface is less than 17 meters, you can't hear any echo.These two factors go together.If the distance is less than 17 meters, the echo will be less than 0.1 seconds thus the ear won't pick it.

Misha Larkins [42]3 years ago
4 0

Answer:

a.  A sound wave reaches the ear and the reflected wave reaches the ear less than 0.1 second later.

Explanation:

bc i said so<< :))) pf

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3. What is the mass of a paratrooper who experiences an air resistance of 400 N and an acceleration of 4.5 m/s2
goblinko [34]

Answer:

88.89kg

Explanation:

The formula for mass is m=F/a. If we plug in the values, we get m=400N/4.5m/s^2. The mass is 88.89kg. We know that the unit is in kg because one newton (N) is 1kg*m/s^2. The m/s^2 is cancelled out by the acceleration, and we are left with kg.

4 0
3 years ago
The flywheel of a steam engine runs with a constant angular velocity of 150 rev/min. When steam is shut off, the friction of the
xz_007 [3.2K]

Answer:

a) -1.14 rev/min²

b) 9900 rev

c) -9.92×10⁻⁴ m/s²

d) 30.8 m/s²

Explanation:

First, convert hours to minutes:

2.2 h × 60 min/h = 132 min

a) Angular acceleration is change in angular velocity over change in time.

α = (ω − ω₀) / t

α = (0 rev/min − 150 rev/min) / 132 min

α = -1.14 rev/min²

b) θ = θ₀ + ω₀ t + ½ αt²

θ = 0 rev + (150 rev/min) (132 min) + ½ (-1.14 rev/min²) (132 min)²

θ = 9900 rev

c) The tangential component of linear acceleration is:

a_t = αr

First,  convert α from rev/min² to rad/s²:

-1.14 rev/min² × (2π rad/rev) × (1 min / 60 s)² = -1.98×10⁻³ rad/s²

Therefore:

a_t = (-1.98×10⁻³ rad/s²) (0.50 m)

a_t = -9.92×10⁻⁴ m/s²

d) The magnitude of the net linear acceleration can be found from the tangential component and the radial component:

a² = (a_t)² + (a_r)²

The radial component is the centripetal acceleration:

a_r = v² / r

a_r = ω² r

First, convert 75 rev/min to rad/s:

75 rev/min × (2π rad/rev) × (1 min / 60 s) = 7.85 rad/s

Find the radial component:

a_r = (7.85 rad/s)² (0.50 m)

a_r = 30.8 m/s²

Now find the net linear acceleration:

a² = (-9.92×10⁻⁴ m/s²² + (30.8 m/s²)²

a = 30.8 m/s²

5 0
3 years ago
At what location in a circuit is the electrical potential energy the greatest
Eduardwww [97]

It's not the potential energy.  It's just the potential.

It's greatest at the positive terminal of the battery or power supply.


4 0
3 years ago
Please Help Me with This
densk [106]

Answer:

Explanation:

a). Find the graph attached for the motion.

b). If a shopper walk 5.4 m westwards then 7.8 m eastwards,

   Distance traveled by the shopper = Distance traveled in eastwards + Distance traveled westwards

                                                            = 5.4 + 7.8

                                                            = 13.2 m

c). Displacement of the shopper = Distance walked westwards - Distance traveled eastwards

                                                      = 5.4 - 7.8

                                                      = -2.4 m

Therefore, magnitude of the displacement of the shopper is = 2.4 m

And the direction of the displacement is eastwards.

8 0
3 years ago
g An astronaut must journey to a distant planet, which is 189 light-years from Earth. What speed will be necessary if the astron
Butoxors [25]

Answer:

The value is v  =  2.999 *10^{8} \  m/s

Explanation:

From the question we are told that

   The time taken to travel to the planet from earth is t = 189 \ light-years

    The  time to be spent on the ship is  t_{s} =  12 \  years

Generally speed can be obtained using the mathematical relation represented below

       t_s  =  2 * t *  \sqrt{1 -  \frac{v^2}{c^2 } }

The 2 in the equation show that the trip is a round trip i.e going and coming back

=>    12 =  2 * 189 *  \sqrt{1 -  \frac{v^2}{(3.0*10^{8})^2 } }

=>     v  =  2.999 *10^{8} \  m/s

5 0
3 years ago
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