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velikii [3]
3 years ago
6

IN which of the following conditions would a person not hear an echo? A. A sound wave reaches the ear, and the reflected wave re

aches the ear less than 0.1 seconds later, B. A person is standing in the range of the sound waves coming from the original sound sources as well as the reflected waves, C. The reflecting wave source is approximately 21.5 meters from the person, D. a person is standing 30 meters in front of the reflecting surface.
Physics
2 answers:
GenaCL600 [577]3 years ago
7 0

Answer:

A. A sound wave reaches the ear, and the reflected wave reaches the ear less than 0.1 seconds later,

Explanation:

Human hear can not differentiate two successive sounds when the period between the sounds is less than 0.1 seconds.When the distance between the source of sound and the reflecting surface is less than 17 meters, you can't hear any echo.These two factors go together.If the distance is less than 17 meters, the echo will be less than 0.1 seconds thus the ear won't pick it.

Misha Larkins [42]3 years ago
4 0

Answer:

a.  A sound wave reaches the ear and the reflected wave reaches the ear less than 0.1 second later.

Explanation:

bc i said so<< :))) pf

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Help please<br> It’s kinda urgent
user100 [1]

Answer:

a = - 50 [m/s²]

Explanation:

To solve this problem we simply have to replace the values supplied in the given equation.

Vf = final velocity = 0.5 [m/s]

Vi = initial velocity = 10 [m/s]

s = distance = 100 [m]

a = acceleration [m/s²]

Now replacing we have:

(0.5)^{2}-(10)^{2} = 2*a*(100)\\0.25-10000=200*a\\200*a=-9999.75\\a =-50 [m/s^{2} ]

The negative sign of acceleration means that the ship slows down its velocity in order to land.

4 0
2 years ago
A 78.5-kg man floats in freshwater with 3.2% of his volume above water when his lungs are empty, and 4.85% of his volume above w
Dima020 [189]

Answer:

A) V_air = 1.295 L

B) Volume is not reasonable

Explanation:

A) Let;

m be total mass of the man

m_p be the mass of the man that pulled out of the water because of the buoyant force that pulled out of the lung

m_3 be the mass above the water with the empty lung

m_5 be the mass above the water with full lung

F_b be the buoyant force due to the air in the lung

V_a be the volume of air inside man's lungs

w_p be the weight that the buoyant force opposes as a result of the air.

Now, we are given;

m = 78.5 kg

m_3 = 3.2% × 78.5 = 2.512 kg

m_5 = 4.85% × 78.5 = 3.80725 kg

Now, m_p = m_5 - m_3

m_p = 3.80725 - 2.512

m_p = 1.29525 kg

From archimedes principle, we have the formula for buoyant force as;

F_b = (m_displaced water)g = (ρ_water × V_air × g)

Where ρ_water is density of water = 1000 kg/m³

Thus;

F_b = w_p = 1.29525 × 9.81

F_b = 12.7064 N

As earlier said,

F_b = (ρ_water × V_air × g)

Thus;

V_air = F_b/(ρ_water × × g)

V_air = 12.7064/(1000 × 9.81)

V_air = 1.295 × 10^(-3) m³

We want to convert to litres;

1 m³ = 1000 L

Thus;

V_air = 1.295 × 10^(-3) × 1000

V_air = 1.295 L

B) From research, the average lung capacity of an adult human being is 6 litres of air.

Thus, the calculated lung volume is not reasonable

4 0
3 years ago
Simplify -2/3 - 3/5<br><br> A) -1/15<br><br> B) -19/15<br><br> C) -3/5<br><br> D) -5/8
Leto [7]
I got B,when you subtract 3/5 from NEGATIVE 2/3 it creates a negative 19 over a positive 15.

7 0
2 years ago
What is an example of radiation? check all that apply
Katen [24]
There are no appropriate examples in the list you provided with your question.

Examples of radiation:

... sunshine to tan your skin
... radio energy to bring you the news
... X-ray to check your teeth
... microwave to heat up the meatloaf
... flashlight to see where you're going
... RF energy to get an MRI of your knee
... infrared radiation from the campfire to warm your tootsies
... UHF radio waves to make a call or check Facebook with your smartphone
4 0
3 years ago
Which of the following is an example of homeostasis?
Bogdan [553]
The answer is : D

Reasoning:
Homeostasis is the body’s balance
3 0
3 years ago
Read 2 more answers
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