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velikii [3]
3 years ago
6

IN which of the following conditions would a person not hear an echo? A. A sound wave reaches the ear, and the reflected wave re

aches the ear less than 0.1 seconds later, B. A person is standing in the range of the sound waves coming from the original sound sources as well as the reflected waves, C. The reflecting wave source is approximately 21.5 meters from the person, D. a person is standing 30 meters in front of the reflecting surface.
Physics
2 answers:
GenaCL600 [577]3 years ago
7 0

Answer:

A. A sound wave reaches the ear, and the reflected wave reaches the ear less than 0.1 seconds later,

Explanation:

Human hear can not differentiate two successive sounds when the period between the sounds is less than 0.1 seconds.When the distance between the source of sound and the reflecting surface is less than 17 meters, you can't hear any echo.These two factors go together.If the distance is less than 17 meters, the echo will be less than 0.1 seconds thus the ear won't pick it.

Misha Larkins [42]3 years ago
4 0

Answer:

a.  A sound wave reaches the ear and the reflected wave reaches the ear less than 0.1 second later.

Explanation:

bc i said so<< :))) pf

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Analogy: atom is to element as ____ is to compound
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Molecule is the answer to what you are looking for

5 0
3 years ago
A torque of 36.5 N · m is applied to an initially motionless wheel which rotates around a fixed axis. This torque is the result
vivado [14]

Answer:

21.6\ \text{kg m}^2

3.672\ \text{Nm}

54.66\ \text{revolutions}

Explanation:

\tau = Torque = 36.5 Nm

\omega_i = Initial angular velocity = 0

\omega_f = Final angular velocity = 10.3 rad/s

t = Time = 6.1 s

I = Moment of inertia

From the kinematic equations of linear motion we have

\omega_f=\omega_i+\alpha_1 t\\\Rightarrow \alpha_1=\dfrac{\omega_f-\omega_i}{t}\\\Rightarrow \alpha_1=\dfrac{10.3-0}{6.1}\\\Rightarrow \alpha_1=1.69\ \text{rad/s}^2

Torque is given by

\tau=I\alpha_1\\\Rightarrow I=\dfrac{\tau}{\alpha_1}\\\Rightarrow I=\dfrac{36.5}{1.69}\\\Rightarrow I=21.6\ \text{kg m}^2

The wheel's moment of inertia is 21.6\ \text{kg m}^2

t = 60.6 s

\omega_i = 10.3 rad/s

\omega_f = 0

\alpha_2=\dfrac{0-10.3}{60.6}\\\Rightarrow \alpha_1=-0.17\ \text{rad/s}^2

Frictional torque is given by

\tau_f=I\alpha_2\\\Rightarrow \tau_f=21.6\times -0.17\\\Rightarrow \tau=-3.672\ \text{Nm}

The magnitude of the torque caused by friction is 3.672\ \text{Nm}

Speeding up

\theta_1=0\times t+\dfrac{1}{2}\times 1.69\times 6.1^2\\\Rightarrow \theta_1=31.44\ \text{rad}

Slowing down

\theta_2=10.3\times 60.6+\dfrac{1}{2}\times (-0.17)\times 60.6^2\\\Rightarrow \theta_2=312.03\ \text{rad}

Total number of revolutions

\theta=\theta_1+\theta_2\\\Rightarrow \theta=31.44+312.03=343.47\ \text{rad}

\dfrac{343.47}{2\pi}=54.66\ \text{revolutions}

The total number of revolutions the wheel goes through is 54.66\ \text{revolutions}.

3 0
3 years ago
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kodGreya [7K]

Answer:

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Explanation:

4 0
3 years ago
Which phrase best describes a machine?
stepan [7]

Answer:

option 1 will be the answer.

Explanation:

hope it helps.

8 0
3 years ago
Read 2 more answers
A piece of wood has a mass of 25g and a volume of <br> 10cm3 What is its density?
Tasya [4]

Answer:

<h3>The answer is 2.5 g/cm³</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume}  \\

From the question we have

density =  \frac{25}{10}  =  \frac{5}{2}  \\

We have the final answer as

<h3>2.5 g/cm³</h3>

Hope this helps you

3 0
3 years ago
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