Where??? complete your question please
Answer:
(A) Original speed= 9.22 m/s
(B) Acceleration= -1.0099 m\s^2
Explanation:
A truck covers 40m in 7.10 secs
The truck slows down at a uniform velocity of 2.05 m/s
(A) The original speed can be calculated as follows
Vo= 2(40)/7.10 - 2.05
= 80/7.10 - 2.05
= 11.2676 - 2.05
= 9.22m/s
(B) The acceleration can be calculated as follows
a= Vf-Vo/t
= 2.05-9.22/7.10
= -7.17/7.10
= -1.0099m/s^2
Answer:
F = 17.3 kN
Explanation:
The normal force must support the weight of the car plus provide for the needed centripetal acceleration.
F = m(g + v²/R ) = 1000(9.8 + 15²/30) = 17,300
Here's the formula for the distance covered by an accelerating body in some amount of time ' T '. This formula is incredibly simple but incredibly useful. It pops up so often in Physics that you really should memorize it:
D = 1/2 a T²
Distance = (1/2)·(acceleration)·(time²)
This question gives us the acceleration and the distance, and we want to find the time.
(9,000 m) = (1/2) (20 m/s²) (time²)
(9,000 m) = (10 m/s²) (time²)
Divide each side by 10 m/s²:
(9,000 m) / (10 m/s²) = (time²)
900 s² = time²
Square root each side:
<em>T = 30 seconds</em>
