1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
otez555 [7]
3 years ago
6

4. Sally applies a horizontal force of 462 N with a rope to drag a wooden crate across a floor with a constant speed. The rope t

ied to the crate is pulled at an angle of 56.00 . c.What work is done by the floor through force of friction between the floor and the crate
Physics
1 answer:
34kurt3 years ago
6 0

Answer:

<em>-6,329.5Joules</em>

<em></em>

Explanation:

Complete question:

Sally applies a horizontal force of 462N with a rope to drag a wooden crate across a floor with a constant speed the rope tied to the crate is pulled at an angle of 56.0degree and sally moves the crate 24.5m. What work is done by the floor through the force of friction between the floor and crate.

Work done = Fd cos theta

F is the horizontal force

d is the distance covered

theta angle of inclination

Substituting into the formula

Workdone  = 462(24.5)cos 56

Workdone = 11,319(0.5592)

Workdone = 6,329.5Joules

Hence the workdone by sally is 6,329.5Joules

<em>The work done by friction will be opposite the work done by sally, hence work done by the floor through force of friction between the floor and the crate is -6,329.5Joules</em>

<em></em>

You might be interested in
Earthquakes create___<br> waves<br> electromagnetic<br> transverse<br> dangerous<br> seismic
LenKa [72]

Answer: In or discussion of earthquake we want to answer the following questions side has moved to the left, we say that the fault is a left-lateral strike-slip fault. Surface waves behave like S-waves in that they cause up and down and side.  Aftershocks are particularly dangerous because that can cause further .

Explanation: Have a nice day!!!

6 0
3 years ago
How much power will be required to force a current of 4.13 amps to flow through a conductor whose resistance is 113 ohms? Use tw
-Dominant- [34]

The power required to force the current of 4.13 A to flow through the conductor is 1927.43 watts

<h3>What is power? </h3>

This is defined as the rate in which energy is consumed. Electrical power is expressed mathematically as:

Power (P) = square current (I²)× resistancet (R)

P = I²R

<h3>How to determine the power</h3>
  • Current (I) = 4.13 A
  • Resistance (R) = 113 ohms
  • Power (P) =?

P = I²R

P = 4.13² × 113

P = 1927.43 watts

Thus, the power required is 1927.43 watts

Learn more about electrical power:

brainly.com/question/64224

#SPJ1

7 0
1 year ago
Question 1 (1 point)
MatroZZZ [7]

Answer:

The work done by the frictional force is 600J.

Explanation:

The work W done by the frictional force is

W= Fd.

Now, F = 60N and d =10m; therefore,

W= (60N)(10m)

\boxed{W = 600J.}

Hence, the work done by friction is 660J.

7 0
2 years ago
15) On a cold day, you take in 4.2 L (i.e., 4.2 x 10-3 m3) of air into your lungs at a temperature of 0°C. If you hold your brea
Rudiy27

Answer:

4.8L ( i.e 4.8 x 10^-3 m3)

Explanation:

Step 1:

Data obtained from the question.

Initial volume (V1) = 4.2L

Initial temperature (T1) = 0°C

Final temperature (T2) = 37°C

Final volume (V2) =?

Step 2:

Conversion of celsius temperature to Kelvin temperature. This is illustrated below

K = °C + 273

T1 = 0°C = 0°C + 273 = 273K

T2 = 37°C = 37°C + 273 = 310K

Step 3:

Determination of the final volume.

Since the pressure is constant,

Charles' Law equation will be applied as shown below:

V1 /T1 = V2/T2

4.2/273 = V2 /310

Cross multiply to express in linear form

273 x V2 = 4.2 x 310

Divide both side by 273

V2 = (4.2 x 310)/273

V2 = 4.8L ( i.e 4.8 x 10^-3 m3)

Therefore, the volume of the air in the lungs at that point is 4.8L ( i.e 4.8 x 10^-3 m3)

3 0
3 years ago
Help me quick!!! please!!
Rudik [331]

Answer:

39.240 W

Explanation:

Let's start by calculating the work done by the engine. We can assume that it is the same work done by the weight of the object to bring it from 40m to the surface: as much energy it takes to bring it up, the same ammount it takes to bring it down. Said work is w= \vec F\cdot \vec{h} = mg h = 1000 \times 9.81\times 40 = 392.400 J

At this point we can simply apply the definition of power, that is P = \frac wt, to get the power of the engine is 39.240 W

4 0
2 years ago
Read 2 more answers
Other questions:
  • Which statements accurately describe Earth’s magnetic field? Check all that apply. The magnetic field lines flow from Earth’s ge
    10·2 answers
  • Solve this.
    8·1 answer
  • An FCC iron-carbon alloy initially containing 0.55 wt% C is exposed to an oxygen-rich and virtually carbon-free atmosphere at 13
    6·1 answer
  • Why does a coastal area have less variation in temperature than a noncoastal area
    12·1 answer
  • What are the 4 spheres that make up the earth
    13·1 answer
  • Find the uncertainty in a calculated electrical potential difference from the measurements of current and resistance. Electric p
    9·1 answer
  • Describe the formation of both positive and negative ions
    7·1 answer
  • A car is travelling along a straight road with speed v measured in m/s. The power P measured in watts required to overcome exter
    8·1 answer
  • Describe the forces that are acting on a person who is standing still on a sidewalk, and identify whether the forces are balance
    6·1 answer
  • A person drives a car for a distance of 450.0 m. The displacement A of the car is illustrated in the drawing. What are the scala
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!