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hjlf
3 years ago
10

When aluminum-27 is bombarded with a neutron, a gamma ray is emitted. what radioactive isotope is produced?

Physics
2 answers:
alexandr402 [8]3 years ago
8 0

Answer:

Go to the excited aluminum-28 isotope

Explanation:

In the processes of nuclear reactions, fundamental changes occur at the level of the atomic nucleus.

Analyze the characteristics of the neutron that has approximately the mass of the proton and has no electric charge, so when being absorbed by the aluminum core the atomic number should not be changed, but the atomic mass should increase by one unit.

The new atom formed is in an excited state and enters the base state with the emission of a high-energy radiation, gamma ray that does not transform the atom

Tthe reaction is:

     ⁷A₂₇ + ⁰n₁ → ⁷Al₂₈ˣ

The symbol "ˣ" means excited

      ⁷Al₂₈ˣ → ⁷Al₂₈ + γ

I am Lyosha [343]3 years ago
5 0
Aluminium 28 i think thats the best isotope for this

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Lacie kicks a football from ground level at a velocity of 13.9 m/s and at an angle of 25.0° to the ground. How long will the bal
Step2247 [10]

Answer:

T = 1.2 s

T = 15.1 m = 15 m

Explanation:

This is a case of projectile motion:

TOTAL TIME OF FLIGHT:

The formula for total time of flight in projectile motion is:

T = 2 V₀ Sinθ/g

where,

T = Total Time of Flight = ?

V₀ = Launch Speed = 13.9 m/s

θ = Launch Angle = 25°

g = 9.8 m/s²

Therefore,

T = (2)(13.9 m/s)(Sin 25°)/(9.8 m/s²)

<u>T = 1.2 s</u>

<u></u>

RANGE OF BALL:

The formula for range in projectile motion is:

R = V₀² Sin2θ/g

where,

R = Horizontal Distance Covered by ball = ?

Therefore,

T = (13.9 m/s)²(Sin 2*25°)/(9.8 m/s²)

<u>T = 15.1 m = 15 m</u>

4 0
3 years ago
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Which of the following is an example of velocity ?
Mademuasel [1]
The correct answer is c because B) is a vector which includes both velocity and direction
7 0
3 years ago
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A 5-kg projectile is fired over level ground with a velocity of 200 m/s at an angle of 25°above the horizontal. Just before it h
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Answer:

the change in thermal energy of the projectile is 43.8 kJ

Explanation:

Given;

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initial velocity of the projectile, v₁ = 200 m/s

final  velocity of the projectile, v₂ = 150 m/s

To determine the the change in the thermal energy of the projectile and air, we consider change in potential and kinetic enrgy of the projectile. Since the projectile was fired over level ground, change in potential energy is zero.

Then, change in thermal energy of the projectile, KE = Δ¹/₂mv²

KE = Δ¹/₂mv² = ¹/₂m(v₁²-v₂²)

KE =  ¹/₂ × 5(200²-150²) = 2.5(17500) = 43750 J = 43.8 kJ

Therefore, the change in thermal energy of the projectile is 43.8 kJ

8 0
3 years ago
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sergejj [24]

Answer:

The new potential energy decreases by the factor of 2 to the old potential energy.

Explanation:

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The capacitor have same potential difference that is V. Hence, the new potential energy is :

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