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2 years ago

When aluminum-27 is bombarded with a neutron, a gamma ray is emitted. what radioactive isotope is produced?

Physics

2 answers:

alexandr402 [8]2 years ago

8 0

Answer:

Go to the excited aluminum-28 isotope

Explanation:

In the processes of nuclear reactions, fundamental changes occur at the level of the atomic nucleus.

Analyze the characteristics of the neutron that has approximately the mass of the proton and has no electric charge, so when being absorbed by the aluminum core the atomic number should not be changed, but the atomic mass should increase by one unit.

The new atom formed is in an excited state and enters the base state with the emission of a high-energy radiation, gamma ray that does not transform the atom

Tthe reaction is:

⁷A₂₇ + ⁰n₁ → ⁷Al₂₈ˣ

The symbol "ˣ" means excited

⁷Al₂₈ˣ → ⁷Al₂₈ + γ

I am Lyosha [343]2 years ago

5 0

Aluminium 28 i think thats the best isotope for this

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$K_{ap} = E_{ph} - 2m_{0p}c^{2} - K_{p}$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2} - 242.85MeV$

$K_{ap} = 2.20 \cdot 10^{3}MeV - 2(1.67 \cdot 10^{-27}kg)(3\cdot 10^{8} \frac {m}{s})^{2}(\frac{1eV}{1.602 \cdot 10^{-19}J})(\frac{1 MeV}{10^{6}eV}) - 242.85MeV$

$K_{ap} = 80.75 MeV$

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