Ask question

Ask question

All categories

3 years ago

7

PLEASE HELP!!!! Assuming a lacrosse ball weighs 5.5 ounces and is made of mainly rubber which has a mass of 82.2 g/mol, how many

particles are in a lacrosse ball?

1 answer:

MissTica3 years ago

8 0

11.412 x 10^23.

EXPLANATION:

5.5 oz = 155.92 g

155.92 g x (1 mol/82.2 g) = 1.8956 mol

(6.02 x 10^23) x 1.8956 = 11.412 x 10^23

You might be interested in

Describe melting of a solid

kvv77 [185]

Answer- The particles in a solid gain enough energy to overcome the bonding forces holding them firmly in place. Typically, during melting, the particles start to move about, staying close to their neighbouring particles, then move more freely.

3 0

4 years ago

Which of the following is part of photosynthesis, but not part of cellular respiration?

Licemer1 [7]

Answer:

A

Explanation:

plants need sunlight to eat. so that's why

8 0

3 years ago

What is the identity of an ion having 46 protons, 42 electrons and 60 neutrons?

Anon25 [30]

Answer:

first u lick it then out some sliva on it then rub it and once the volcano erupts u put it back in ur mouth and blow real hard ok!

Explanation:

repeat this process till the dong bleeds!

3 0

3 years ago

Th e molar absorption coeffi cient of a substance dissolved in water is known to be 855 dm3 mol−1 cm−1 at 270 nm. To determine t

Olegator [25]

Answer : The percentage reduction in intensity is 79.80 %

Explanation :

Using Beer-Lambert's law :

$A=\epsilon \times C\times l$

$A=\log \frac{I_o}{I}$

$\log \frac{I_o}{I}=\epsilon \times C\times l$

where,

A = absorbance of solution

C = concentration of solution = $3.25mmol.dm^{3-}=3.25\times 10^{-3}mol.dm^{-3}$

l = path length = 2.5 mm = 0.25 cm

$I_o$ = incident light

$I$ = transmitted light

$\epsilon$ = molar absorptivity coefficient = $855dm^3mol^{-1}cm^{-1}$

Now put all the given values in the above formula, we get:

$\log \frac{I_o}{I}=(855dm^3mol^{-1}cm^{-1})\times (3.25\times 10^{-3}mol.dm^{-3})\times (0.25cm)$

$\log \frac{I_o}{I}=0.6947$

$\frac{I_o}{I}=10^{0.6947}=4.951$

If we consider $I_o$ = 100

then, $I=\frac{100}{4.951}=20.198$

Here 'I' intensity of transmitted light = 20.198

Thus, the intensity of absorbed light $I_A$ = 100 - 20.198 = 79.80

Now we have to calculate the percentage reduction in intensity.

$\% \text{reduction in intensity}=\frac{I_A}{I_o}\times 100$

$\% \text{reduction in intensity}=\frac{79.80}{100}\times 100=79.80\%$

Therefore, the percentage reduction in intensity is 79.80 %

3 0

4 years ago

Hemoglobin is the protein that transports oxygen in mammals. Different species of mammals have slightly different forms of hemog

Anna35 [415]

Answer;

= 64561.95 g/mole

Explanation;

mass of Fe in 100g = .346g

= .346 / 55.8452 moles

= 0.0061957 moles

These represent 4 moles of Fe in the molecule so moles of hemaglobin

= 0.0061957/4

= 0.0015489 moles

these are in 100 g so mass of 1 mole = 100 / 0.0015489

= 64561.95 g / mole

molar mass of hemoglobin = 64561.95 g/mole

6 0

4 years ago