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2 years ago

PLZZZZZ HELP MEEEEEEEE

Chemistry

2 answers:

iren2701 [21]2 years ago

7 0

Answer: A negative charge or 1

Explanation: well if the positive charges in lightning need to connect to negative charges and in an attempt to do that lightning and static electricity is like lightning.

ohaa [14]2 years ago

5 0

Answer:

A negative and unchanged :)

Explanation:

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If 1.8 L of water is added to 2.5 L of a 7.0 M KOH solution, what is the molarity of the new solution?

e-lub [12.9K]

Molarity= (number of moles of that substance) / (Volume of solution in litres)

7= (number of moles of HCl) / 0.05

Thus,

Number of moles of HCl = 7 x 0.05 = 0.35

The number of moles of HCl will remain unchanged.

Now, for new solution,

0.35= 0.35 / (New volume of solution in litres)

Thus,

New volume = 1 litre

Thus, amount of water added = 1- 0.05 litre = 5.0 M

6 0

3 years ago

Under which conditions can an eclipse occur?

NeX [460]

Answer:

Moon blocks the sun

Explanation:

I hope this is right because i did this question 2 years ago.

8 0

3 years ago

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Is the equation balanced or unbalanced?

AlekseyPX

Explanation:

The equation is balanced

5 0

3 years ago

Using average bond enthalpies (linked above), estimate the enthalpy change for the following reaction: OF2(g) + H2O(g)O2(g) + 2H

andreev551 [17]

Answer:

Ehthalpy change for the reaction is -323 kJ

Explanation:

Enthalpy change for a reaction, $\Delta H_{rxn}$ is given as:

$\Delta H_{rxn}=\sum [n_{i}\times (E_{bond})_{i}]-\sum [n_{j}\times (E_{bond})_{j}]$

Where $(E_{bond})_{i}$ and $(E_{bond})_{j}$ represents average bond energy in breaking "i" th bond and forming "j" th bond respectively. $n_{i}$ and $n_{j}$ are number of moles of bond break and form respectively.

Reaction: $F-O-F+H-O-H\rightarrow O=O+2H-F$

Here, 2 moles of O-F bond and 2 moles of of O-H bond are broken

1 mol of O=O and 2 moles of H-F bonds are formed.

So, $\Delta H_{rxn}=[2mol\times E_{O-F}]+[2mol\times E_{O-H}]-[1mol\times E_{O=O}]-[2mol\times E_{H-F}]$

So, $\Delta H_{rxn}=[2mol\times 190kJ/mol]+[2mol\times 463kJ/mol]-[1mol\times 495kJ/mol]-[2mol\times 567kJ/mol]=-323kJ$

3 0

4 years ago

A radioactive element having and atomic number 82 and atomic mass 214 emits a beta particle. The resulting element is:______.

aalyn [17]

Answer:

$\frac{214}{83} Bi$

Explanation:

In beta emission, a neutron is converted into a proton thereby reducing the neutron:proton (N/P) ratio.

When a beta emission occurs, the mass number remains the same while the nuclear charge increases by one unit. The daughter nucleus is found one place to the right of its parent in the periodic table.

5 0

3 years ago