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denis23 [38]
2 years ago
8

If 72 = 12x, what does x equal?

Mathematics
1 answer:
CaHeK987 [17]2 years ago
6 0

Answer:

x=6

Step-by-step explanation:

So, x is our unknown variable. An so you have to ask yourself, what times 12= 72? The answer would be 6, because 12x6=72

The proper way to do it, would be to divide 12/12 so you isolate the variable, and what you do to one side, you do to the other, so divide 72 by 12 and you get 6! Hope this helps!

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Please help me solve this question will give you braisnlt !
DIA [1.3K]

Answer:

s = 54m +160

Step-by-step explanation:

Given: The attachment

Required: Determine the equation

We start by picking any two equivalent points on the table:

(m_1,s_1) = (2,268)

(m_2,s_2) = (4,376)

Next, we determine the slope, M:

M = \frac{s_2 - s_1}{m_2 - m_1}

M = \frac{376 - 268}{4-2}

M = \frac{108}{2}

M = 54

The equation is then calculated as:

s - s_1 = M(m - m_1)

Where:

M = 54

(m_1,s_1) = (2,268)

So, we have:

s - 268 = 54(m - 2)

Open bracket

s - 268 = 54m - 108

Collect like terms

s = 54m - 108 + 268

s = 54m +160

Hence, the equation is: s = 54m +160

6 0
2 years ago
Cellus
mote1985 [20]

Answer:

y = 6 when x = 18

Step-by-step explanation:

The appropriate formula for this direct proportion is y = kx, where k is the constant of proportionality.

We know y = 3 when x = 9:  3 = k(9)

This yields k = 3/9, or k = 1/3

Then the formula is y = (1/3)x

and when x = 18, y = (1/3)(18) = 6

y = 6 when x = 18

4 0
2 years ago
Tossing a regular coin 3 times, what is the probability of getting heads every time? 4)
larisa [96]

The probability of getting heads on the first toss is  1/2 .

Then, the probability of getting heads on the second toss is  1/2 .

Then, the probability of getting heads on the third toss is  1/2 .

The probability of all three things happening is ...

                 (1/2) x (1/2) x (1/2)  =  1/8  =  0.125  =  12.5% .



6 0
3 years ago
Read 2 more answers
Seperate the number 53 into 3 parts so that the second number is 3 less than the first number and the third number is twice the
irga5000 [103]
Hello,

Let a the first, b the second and c the third.
a+b+c=53
b=a/3
c=2a
==>a+a/3+2a=53
==>10a/3=53
==>a=15.9
c=2*a=2*15.9=31.8
b=a/3=15.9/3=5.3

Proof: a+b+c=15.9+5.3+31.8=53

The second number is 5.3
7 0
3 years ago
Answers to these! Need ASAP due tomorrow
Aleks04 [339]
Try Photomath Even scans the problem from your paper
#2

3 0
3 years ago
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