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svetoff [14.1K]
3 years ago
12

Ninth grade math help me PLEASEEEE PLEASE

Mathematics
1 answer:
dusya [7]3 years ago
3 0

Answer:

I believe the answer is D.

Step-by-step explanation:

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<em>(C). b + (2 × 35) = 180; b = 110°</em>

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2 years ago
Solve for the values of x in the equation: <br> 2^(x) = 4x.
Eva8 [605]

There are two of them. 

I don't know a mechanical way to 'solve' for them.

One can be found by trial and error:

x=0 . . . . . 2^0 = 1 . . . . . 4(0) = 0 . . . . . no, that doesn't work
x=1 . . . . . 2^1 = 2 . . . . . 4(1) = 4 . . . . . no, that doesn't work
x=2 . . . . . 2^2 = 4 . . . . . 4(2) = 8 . . . . . no, that doesn't work
x=3 . . . . . 2^3 = 8 . . . . . 4(3) = 12 . . . . no, that doesn't work
<em>x=4</em> . . . . . 2^4 = <em><u>16</u></em> . . . . 4(4) = <em><u>16</u></em> . . . . Yes !  That works !       yay !

For the other one, I constructed tables of values for 2^x and (4x)
in a spread sheet, then graphed them, and looked for the point
where the graphs of the two expressions cross.

The point is near, but not exactly,         <em>x = 0.30990693...

</em>
If there's a way to find an analytical expression for the value, it must involve
some esoteric kind of math operations that I didn't learn in high school or
engineering school, and which has thus far eluded me during my lengthy
residency in the college of hard knocks.<em> </em> If anybody out there has it, I'm
waiting with all ears.<em>

</em>
7 0
2 years ago
Read 2 more answers
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