Answer:
Explanation:
If one mole of carbon monoxide has a mass of 28.01 g and one mole of carbon dioxide has a mass of 44.01 g , it follows that the reaction produces 44.01 g of carbon dioxide for every 28.01 g of carbon monoxide.
87.8 , 31 Celsius=87.8(88) in Fahrenheit
D) All three bulbs would go out because the circuit would no longer have a ground thereby deeming it "open".
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Empirical formula: Li4OH
Answer:
1 mole: 44.771 g
1 gram = 0.022 mole
Explanation:
Element: Li
Percentage by mass: 62.01%
Number of atoms: 4
Mass of atom;: 6.941
Element: O
Percentage by mass: 35.74%
Number of atoms: 1
Mass of atom: 15.9994
Element: H
Percentage by mass: 2.25%
Number of atoms: 1
Mass of atom: 1.00794
