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vampirchik [111]
3 years ago
5

In a galvanic cell, electrons flow from the ________ to the _______ .

Physics
1 answer:
s2008m [1.1K]3 years ago
7 0

Answer:

E.

Explanation:

In a galvanic cell, electrons flow from the anothe to the cathode.

I hope you got the answer

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The moon’s period of revolution is 27 1/3 days, and its period of rotation about its axis is _____.
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It lasts 29 1/2 days.
-the sidereal month- is the true period of the moon's revolution around Earth. It lasts 27 1/3 days.
-the difference of 2 days between the synodic and sidereal cycles is due to the Earth- moon system also moving in an orbit around the sun.
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3 years ago
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The difference in outcome between the potential energy in a marshmallow burned over a campfire on the end of a stick and in one
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Answer:

How fast and efficient the energy is released.

Explanation:

Before burning the marshmallow energy is stored in it in the form of chemical bond energy or chemical potential energy. So upon burning this energy is released. So there will be a difference in energy release from a burned marshmallow and the one we eat straight from package.

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3 years ago
On a sunny day, does a bird or an aeroplane flying high in the sky cast its
Ilia_Sergeevich [38]

Answer:

Hope it helps

Explanation:

The higher the bird flies, the bigger the shadow it casts, however, for the shadow to be visible enough the plane or bird would have to be close to the line directly from the sun.

3 0
3 years ago
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NEED HELP
aniked [119]

Answer:

I = 0.25 [amp]

Explanation:

To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance.

V = I*R

where:

V = voltage [Volt]

I = amperage or current [amp]

R = resistance [ohm]

Since all resistors are connected in series, the total resistance will be equal to the arithmetic sum of all resistors.

Rt = 2 + 8 + 14

Rt = 24 [ohm]

Now clearing I for amperage

I = V/Rt

I = 6/24

I = 0.25 [amp].

5 0
3 years ago
A fisherman has caught a very large, 5.0 kg fish from a dock that is 2.0 m above the water. He is using lightweight fishing line
sergeinik [125]

Answer:

The least amount of time in which the fisherman can raise the fish to the  dock without losing it is t= 2 seconds.

Explanation:

m= 5 kg

h= 2m

Fmax= 54 N

g= 9.8 m/s²

W= m * g

W= 49 N

F= Fmax - W

F= 5 N

F=m*a

a= F/m

a= 1 m/s²

h= a * t²/2

t= √(2*h/a)

t= 2 seconds

6 0
3 years ago
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