Answer:
a) 378Ns
b) 477.27N
Explanation:
Impulse is the defined as the product of the applied force and time taken. This is expressed according to the formula
I = Ft = m(v-u)
m is the mass = 70kg
v is the final velocity = 5.4m/s
u is the initial velocity = 0m/s
Get the impulse
I = m(v-u)
I = 70(5.4-0)
I = 70(5.4)
I = 378Ns
b) Average total force is expressed as
F = ma (Newton's second law)
F = m(v-u)/t
F = 378/0.792
F = 477.27N
Hence the average total force experienced by a 70.0-kg passenger in the car during the time the car accelerates is 477.27N
Answer:
a) 12.8 N
b) 3.2 m/s²
Explanation:
I'm guessing the period is 0.5π s.
Period of a spring in simple harmonic motion is:
T = 2π √(m/k)
Given T = 0.5π and m = 2 kg:
0.5π = 2π √(2/k)
0.25 = √(2/k)
0.0625 = 2/k
k = 32
The spring constant is 32 N/m, and the maximum displacement is 0.4 m. The maximum force can be found with Hooke's law:
F = kx
F = (32 N/m) (0.4 m)
F = 12.8 N
The acceleration can be found with Newton's second law:
∑F = ma
kx = ma
(32 N/m) (0.2 m) = (2 kg) a
a = 3.2 m/s²
Assuming hat both gases obey charles' law at all temperatures are at the same pressure
Answer:
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