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quester [9]
3 years ago
9

To properly record a measurements, you must record which of the following?

Physics
1 answer:
serg [7]3 years ago
5 0
I'm not too sure about this but unit is definitely one of the answers. If "number" refers to (for example) the "6" in 6 inches then it should also count. I think "symbol" could also just be unit so I'm not sure about that.
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Describe the responses of the human ear to sound waves coming from the
maria [59]

If the sound comes from the right side, the waves reach the right ear before the left ear. if the sound comes from the left side, the waves reach the left ear before the right ear. The difference between the phases of waves reaching both ears is detected by the ears and then interpreted by the brain

8 0
3 years ago
Use this formula to solve this problem:
Maslowich
Well, you gave us the formula to calculate power from work and time,
but you didn't give us the formula for work.  We have to know that.

             Work = (force) x (distance)

The work to raise Sara to the top of the hill is

               Work = (300 N) x (15 meters)

                         =   4,500 newton-meters  =  4,500 joules .

Now we're ready to use the formula that you gave us.  (Thank you.)

                Power = (work) / (time)

                            = (4,500 joules) / (10 seconds)

                            450 joules/second  =  450 watts.       
6 0
3 years ago
Read 2 more answers
ماهي قوة التركيز من العين عندما ينضر الكاءن من ٢٠ الى ٥٠٠ من عينه
Debora [2.8K]

Answer:

What is the power of focus from the eye when a subject looks from 20 to 500 from its eye?

Explanation:

Is that your question?

4 0
2 years ago
Add me and ill add you back!! you have to bc i just gave you free coins :)​
Rainbow [258]

Answer:

yoooooooooooooooooooo

Explanation:

6 0
3 years ago
Read 2 more answers
A sinusoidal wave of angular frequency 1,203 rad/s and amplitude 3.1 mm is sent along a cord with linear density 3.9 g/m and ten
kobusy [5.1K]

Answer:

18.7842493212 W

Explanation:

T = Tension = 1871 N

\mu = Linear density = 3.9 g/m

y = Amplitude = 3.1 mm

\omega = Angular frequency = 1203 rad/s

Average rate of energy transfer is given by

P=\dfrac{1}{2}\sqrt{T\mu}\omega^2y^2\\\Rightarrow P=\dfrac{1}{2}\sqrt{1871\times 3.9\times 10^{-3}}\times 1203^2\times (3.1\times 10^{-3})^2\\\Rightarrow P=18.7842493212\ W

The average rate at which energy is transported by the wave to the opposite end of the cord is 18.7842493212 W

7 0
3 years ago
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