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3 years ago

The price of a television is $567.31. The state sales tax rate is 8.3%.

Mathematics

2 answers:

liraira [26]3 years ago

7 0

Answer:

$2.64957x10$

$8547 \times 31$

$= 264951$

Tems11 [23]3 years ago

3 0

8.3%= 0.083

567.31 * .083 = 47.086 = 47.09

567.31+47.09= $614.40

Total cost is $614.40

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A graph shows the horizontal axis numbered 2 to 8 and the vertical axis numbered 10 to 50. A line increases from 0 to 4 then dec

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Answer:

very easy A graph shows the horizontal axis numbered 2 to 8 and the vertical axis numbered 10 to 50. A line increases from 0 to 4 then decreases from 4 to 9.

Which type of function best models the data shown on the scatterplot?

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3 years ago

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A retailer allowed 12% discount and sold a T-shirt at a loss of Rs 16. If he had sold it at 10% discount he would have gained Rs

Murrr4er [49]

Answer: Marked Prixe = Rs. 1800

Step-by-step explanation:

Let the marked price be M

1) A retailer allowed 12% discount and sold a T-shirt at a loss of Rs 16.

SP = 0.88M

CP - SP = 16

CP = 16 + SP

CP = 16 + 0.88M

2) If he had sold it at 10% discount he would have gained Rs 20.

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3 years ago

Multiply (x^2 - 3x + 4)(-2x^2 + 4x - 1) <br><br>Show the steps on how to solve please.

Firdavs [7]

-2x^4 + 10x^3 - 21x^2 + 19x - 4

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2 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

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3 years ago

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Katen [24]

The trip back the boat will travel only 30 miles because the trip doubled the hrs.

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