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Vanyuwa [196]
3 years ago
7

The price of a television is $567.31. The state sales tax rate is 8.3%.

Mathematics
2 answers:
liraira [26]3 years ago
7 0

Answer:

2.64957x10

8547 \times 31

= 264951

Tems11 [23]3 years ago
3 0
8.3%= 0.083

567.31 * .083 = 47.086 = 47.09

567.31+47.09= $614.40

Total cost is $614.40
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Step-by-step explanation:

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1) Find the missing side. Give your<br> answer in simplest radical form.
gladu [14]

Answer:

x = 4√5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

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<u>Trigonometry</u>

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

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Step-by-step explanation:

<u>Step 1: Define</u>

Leg <em>a</em> = 8

Leg <em>b</em> = 4

Hypotenuse <em>c</em> = <em>x</em>

<em />

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute in variables [Pythagorean Theorem]:                                            8² + 4² = x²
  2. Evaluate exponents:                                                                                         64 + 16 = x²
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The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

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2 years ago
Joseph has 1/2 of a sub left after lunch. He eats 1/4 of this amount for snack. what fraction of a whole sub did Joseph eat fo
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Answer:

Step-by-step explanation:

I believe the answer would be 1/4 of the sub. Because they asked about the whole sub. And it says he ate 1/4 of the amount of that half of the sub for snack. So out of the whole sandwich it would be 1/4!

If it’s not the answer your looking for you can take it off...

But...

Hope it helps

7 0
3 years ago
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