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sashaice [31]
3 years ago
9

Tyler used

Mathematics
2 answers:
Evgesh-ka [11]3 years ago
8 0

Answer:

1 3/4 gallons of paint

Step-by-step explanation:

sorry if wrong

nika2105 [10]3 years ago
3 0
You need to find a common denominator I chose 28 so I multiplied 4 by 7 and that gives you 28 and you have to do the same thing to the top that you did to the bottom so I multiplied 11 by 7 as well which gave me a fraction of 77/28 then I multiplied 7 by 4 to get 28 and multiplied the top by 4 to get a fraction of 20/28 then I added 8 to 20/28 and to 77/28 to get 28/28 (the whole fence) and 85/28 (the paint you need to cover the whole fence) then I simplified my answer by seeing how many times 28 fit into 85 and it fits 3 times with a remainder of 1 so the simplified answer I got was 3 and 1/28 gallons of paint to cover the whole fence.
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g In a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained
Marat540 [252]

Answer:

95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

Step-by-step explanation:

We are given that in a certain rural county, a public health researcher spoke with 111 residents 65-years or older, and 28 of them had obtained a flu shot.

Firstly, the Pivotal quantity for 95% confidence interval for the population proportion is given by;

                          P.Q. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of residents 65-years or older who had obtained a flu shot = \frac{28}{111} = 0.25

          n = sample of residents 65-years or older = 111

          p = population proportion of residents who were getting the flu shot

<em>Here for constructing 95% confidence interval we have used One-sample z test for proportions.</em>

<u>So, 95% confidence interval for the population proportion, p is ;</u>

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5% level

                                                of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.96) = 0.95

P( -1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

P( \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.95

<u>95% confidence interval for p</u> = [ \hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } },\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ]

   = [ 0.25-1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } } , 0.25+1.96 \times {\sqrt{\frac{0.25(1-0.25)}{111} } } ]

   = [0.169 , 0.331]

Therefore, 95% confidence interval for the percent of the 65-plus population that were getting the flu shot is [0.169 , 0.331].

7 0
3 years ago
Y + y + y + y + ytytyty<br> Collect like terms
Ostrovityanka [42]
This would be 4y + 1ytytyty I believe considering they’re all bunched together in the last bit.
7 0
3 years ago
4+2(8²×4²)+6+4+6+6+6+2+2​
mash [69]

Answer: =2084

 

4+2(82)(42)+6+4+6+6+6+2+2

=4+264(42)+6+4+6+6+6+2+2

=4+2(64)(16)+6+4+6+6+6+2+2

=4+(2)(1024)+6+4+6+6+6+2+2

=4+2048+6+4+6+6+6+2+2

=2052+6+4+6+6+6+2+2

=2058+4+6+6+6+2+2

=2062+6+6+6+2+2

=2068+6+6+2+2

=2074+6+2+2

=2080+2+2

=2082+2

=2084

 

4 0
3 years ago
Read 2 more answers
HELPPPPPPPP I am taking it now
Elena-2011 [213]

Answer:

I'm pretty sure the answer is -a²b and 5a²b

Step-by-step explanation:

8 0
3 years ago
Complete the following sentence.
coldgirl [10]

Answer:arc lengths; radius

l guzz.. sry if wrong....

7 0
3 years ago
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