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svetoff [14.1K]
3 years ago
7

Using science terms like force, mass, energy, and inertia, describe how you could get an object to fly a further distance in a c

atapult?
Physics
1 answer:
qaws [65]3 years ago
5 0

i need the same question

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An ideal spring is fixed at one end. A variable force F pulls on the spring. When the magnitude of F reaches a value of 43.8 N,
maw [93]

A force of 43.8 N is required to stretch the spring a distance of 15.5 cm = 0.155 m, so the spring constant <em>k</em> is

43.8 N = <em>k</em> (0.155 m)   ==>   <em>k</em> = (43.8 N) / (0.155 m) ≈ 283 N/m

The total work done on the spring to stretch it to 15.5 cm from equilibrium is

1/2 (283 N/m) (0.155 m)² ≈ 3.39 J

The total work needed to stretch the spring to 15.5 cm + 10.4 cm = 25.9 cm = 0.259 m from equilibrium would be

1/2 (283 N/m) (0.259 m)² ≈ 9.48 J

Then the additional work needed to stretch the spring 10.4 cm further is the difference, about 6.08 J.

5 0
3 years ago
What is the action force and the reaction force when you sit down on a chair
Licemer1 [7]
The action force is when you are putting your weight on the chair when you are sitting down. the reaction force is the force exerted by the chair that pushes up on your body and is equal to your weight. 
4 0
3 years ago
When is the next total solar eclipse in north america
matrenka [14]

April 8, 2024

The path of totality will cross Mexico, the USA, and Canada.

5 0
3 years ago
The free length of the spring that is attached to the 0.3-lb slider is 3 in. If the slider is released from rest when x = 6 in.,
hichkok12 [17]

Answer:

a = 64 ft / s²

Explanation:

The force in a spring is given by Hooke's law

          F = -k x

Let's use the initial data to calculate the spring constant

         k = F / x

Reduscate to the English system

          x = 3 in (1foot/12 in) =0.25 foot

         k = 0.3 / 0.25

         k = 1.2  lb / foot

Now we can use Newton's second law

        F = ma

        a = F / m

        a = -k x / m

        m = w / g

        m = 0.3 / 32 = 0.009375

         x= 6 in (1foot /12 in)= 0.5 foot

        a = - 1.2  0.5  / 0.009375

        a = 64 ft / s²

5 0
3 years ago
A convex refracting surface has a radius of 12 cm. Light is incident in air (n = 1) and refracted into a medium with an index of
OLga [1]

Answer:

<h2>36cm from the surface</h2>

Explanation:

Equation of refraction of a lens is expression according to the formula given below;

\dfrac{n_2}{v} = \dfrac{n_1}{u}=  \dfrac{n_2-n_1}{R}

R is the radius of curvature of the convex refracting surface = 12cm

v is the image distance from the refracting surface

u  is the object distance from the refracting surface

n₁ and n₂ are the refractive indices of air and the medium respectively

Given parameters

R = 12 cm

u = \infty (since light incident is parallel to the axis)

n₁  = 1

n₂  = 1.5

Required

<em>focus point of the light that is incident and parallel to the central axis (v)</em>

<em />

Substituting this values into the given formula we will have;

\dfrac{1.5}{v} - \dfrac{1}{\infty}=  \dfrac{1.5-1}{12}\\\\\dfrac{1.5}{v} -0=  \dfrac{0.5}{12}\\\\\dfrac{1.5}{v}=  \dfrac{0.5}{12}\\\\

Cross multiply

1.5*12 = 0.5*v\\ \\18 = 0.5v\\\\v = \frac{18}{0.5}\\ \\v = 36cm

Hence  Light incident parallel to the central axis is focused at a point 36cm from the surface

6 0
3 years ago
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