Explanation:
a) From Coulombs law,
F = (kq1q2)/r²...............1
F = 10 N
r = 10m
k = 9 × 10^9 m/F
q1 = q2
from equation 1, make q the subject
q = (Fr²)/2k
q = (10×10²)/(2×9×10^9)
q = 1000/1.8×10^10
q = 5.556×10^-8 C
b) K = k/ko
k = Kko = 10times permittivity of free-space
Goodluck
Answer:
Solon,
total mass (kg)= 100kg
height (h)= 25m
acceleration due to gravity = 9.8m/s²
so,
work done =m*g*h
= 100*9.8*25
= 24,500 joule
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