Heat required to raise the temperature of mercury is given as
here given that
m = 56 g
s = specific heat capacity of mercury = 0.140 J/g C
now here we have
so it required 2265.76 J of heat
The unit for the speed was not given
If speed is 15km/h
and distance is 1.2km
Then using the formula
Speed = distance/time
Time = t
15 = 1.2/t
15t = 1.2
t = 1.2/15
t = 0.08hrs
But
1hr = 60seconds
0.08hrs = t
t = 60(0.08)
t = 4.8s
Answer:
37.33m
Explanation:
To calculate the distance using d= 1/2 at², the time taken for this projectile object (ball) must be calculated.
Time of a projectile = 2u sinθ/ g
Where u = velocity = 27m/s
g = 9.8m/s²
θ = 30°
T = 2usinθ/ g
T = 2 × 27 × sin 30°/9.8
T = 54sin30°/9.8
T = 27/9.8
T = 2.755
T = 2.76s
If the time taken for the ball to move is 2.76s, the distance travelled is:
D = 1/2at²
D = 1/2 × 9.8 × 2.76²
D = 1/2 × 9.8 × 7.6176
D = 74.65248/2
D = 37.33m
The horizontal distance the ball travels is 37.33m
