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Sidana [21]
3 years ago
8

What's the difference between a molecule and a particle​

Chemistry
1 answer:
zepelin [54]3 years ago
3 0

Answer:

A particle is the smallest possible piece of something, of matter, while a molecule is the smallest particle of an element, for example H2 is molecule, smallest particle of the hydrogen in the air, and the molecule is two or more atoms held with chemical bonds, and have chemical properties.

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Name 2 ways forelimbs are different than hind limbs.
Allisa [31]
<span>Hind limbs will typically be stronger than forelimbs. For some animals this is because they are used for self-defense (a horse or donkey kicking, for example). Forelimbs are not going to be as strong and are often used for feeding oneself, and not intended to be as weight bearing in many mammals.</span>
4 0
3 years ago
What is the number of electrons shared in the multiple carbon-carbon bond in one molecule of 1-pentyne?
jeka57 [31]
Where the options are?
8 0
3 years ago
Is the equation for reaction 1 balanced? Explain your reasoning. If the reaction is not balanced, then state how you would balan
sveticcg [70]

Answer:

Reaction is already balanced

Explanation:

The equation in reaction 1 is given as;

CH3COOH + NaHCO3 --> CO2 + H2O +  Na+   +  CH3COO-

The reaction is already balanced. This is because the umber of atoms of elements in the reactant is equal to that of the products

Carbon

Reactant = 2 + 1 = 3

Product = 2 + 2 = 3

Hydrogen

Reactant = 3 + 1 + 1 = 5

Product = 2 + 3 = 5

Oxygen

Reactant = 2 + 3 = 5

Product = 2 +1 + 2 = 5

Sodium

Reactant = 1

Product = 1

3 0
3 years ago
Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 1.731.
Amanda [17]

Answer:

The answer to your question is letter c) 6.09 g of sodium and 9.38 g of chlorine.

Explanation:

This problem is solve using rule of three

We know that the proportion Sodium to Chloride is 1 to 1 in sodium chloride, so we have to look for this proportion in the options

AM Sodium = 23 g

AM Chlorine = 35.5 g

                 Sodium                                     Chlorine

           23 g ---------------- 1 mol              35.5 g -------------- 1 mol

       1713.73g -------------    x               2666.6 g -------------    x

          x = 1713.73/23 = 74.51                     x = 2666.6/35.5 = 75.12

    These values are very similar, we have to look for the proportion in the options

a)      6.09g of sodium = 0.26 mol

      4,87 g of chlorine = 0.14 mol           These numbers are not very similar

b) We have 0.26 mol of Na

                  0.037 mol of Cl                      This is not the answer

c) We have 0.26 mol of Na

                  0.26 mol of Cl                     These numbers are the same, the proportion is 1:1, this is the answer

d) We have 0.26 mol of Na

                   0.36 mol of Cl                    This is not the answer

8 0
3 years ago
The solubility of oxygen in lakes high in the Rocky Mountains is affected by the altitude. If the solubility of O2 from the air
IceJOKER [234]

Answer:

1.75\cdot 10^{-4} M

Explanation:

Henry's law states that the solubility of a gas is directly proportional to its partial pressure. The equation may be written as:

S = k_H p^o

Where k_H is Henry's law constant.

Our strategy will be to identify the Henry's law constant for oxygen given the initial conditions and then use it to find the solubility at different conditions.

Given initially:

S_1 = 2.67\cdot 10^{-4} M

Also, at sea level, we have an atmospheric pressure of:

p = 1.00 atm

Given mole fraction:

\chi_{O_2} = 0.209

According to Dalton's law of partial pressures, the partial pressure of oxygen is equal to the product of its mole fraction and the total pressure:

p^o = \chi_{O_2} p

Then the equation becomes:

S_1 = k_H \chi_{O_2} p

Solve for k_H:

k_H = \frac{S_1}{\chi_{O_2} p} = \frac{2.67\cdot 10^{-4} M}{0.209\cdot 1.00 atm} = 0.001278 M/atm

Now we're given that at an altitude of 12,000 ft, the atmospheric pressure is now:

p = 0.657 atm

Apply Henry's law using the constant we found:

S_2 = k_H \chi_{O_2} p = 0.001278 M/atm\cdot 0.209\cdot 0.657 atm = 1.75\cdot 10^{-4} M

8 0
3 years ago
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