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Sidana [21]
3 years ago
8

What's the difference between a molecule and a particle​

Chemistry
1 answer:
zepelin [54]3 years ago
3 0

Answer:

A particle is the smallest possible piece of something, of matter, while a molecule is the smallest particle of an element, for example H2 is molecule, smallest particle of the hydrogen in the air, and the molecule is two or more atoms held with chemical bonds, and have chemical properties.

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BartSMP [9]

Answer:

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Explanation:            

3 0
3 years ago
Show All Work For Brainliest
sattari [20]

Answer:

1) <u>16.8 L CO2</u>

<u>2) 36.96 L NH3</u>

<u>3) </u> <u>9.88 L CO2 </u>

<u>4) 56.99 L H2O</u>

Explanation:

How many liters of carbon dioxide gas will be produced when 75.0 g of calcium carbonate decomposes to form calcium oxide when at STP?

CaCO3 → CaO + CO2

Moles calcium carbonate = 75.0 grams / 100.09 g/mol

Moles calcium carbonate = 0.750 moles

For 1 mol CaCO3 we'll have 1 mol CaO and 1 mol CO2

For 0.750 moles CaCO3 we'll have 0.750 moles CO2

1 mol = 22.4 L

0.750 moles CO2 = 0.750 *22.4 L =<u> 16.8 L CO2</u>

2. Hydrogen gas reacts with 23.1 g of nitrogen gas to produce ammonia (NH3). What volume of ammonia will be produced at STP?

3H2 + N2 → 2NH3

Moles N2 = 23.1 grams / 28.0 g/mol

Moles N2 = 0.825 moles

For 3 moles H2 we need 1 mol N2 to produce 2 moles NH3

For 0.825 moles N2 we'll have 2*0.825 = 1.65 moles NH3

1 mol = 22.4 L

1.65 mol = 1.65 * 22.4 L = <u>36.96 L NH3</u>

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3. Iron (III) oxide reacts with carbon monoxide to form iron and carbon dioxide. How many liters of carbon dioxide will be produced from 23.5 g of iron (III) oxide when at STP?

Fe2O3 + 3CO → 2Fe + 3CO2

Moles Fe2O3 = 23.5 grams / 159.69 g/mol

Moles Fe2O3 = 0.147 moles

For 1 mol Fe2O3 we need 3 moles CO to produce 2 moles Fe and 3 moles CO2

For 0.147 moles Fe2O3 we'll have 3*0.147 = 0.441 moles CO2

1 mol = 22.4 L

0.441 moles = 22.4 * 0.441 = <u>9.88 L CO2 </u>

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4.How many liters of water vapor would be produced in the combustion of 12.5L of ethane, C2H6 at STP?

2C2H6 + 7O2 →4CO2 + 6H2O

22.4 L = 1 mol

12.5 L = 0.848 moles C2H6

For 2 moles C2H6 we need 7 moles O2 to produce 4 moles CO2 and 6 moles H2O

For 0.848 moles C2H6 we'll have 3*0.848 =  2.544 moles H2O

1 mol = 22.4 L

2.544 moles = 22.4 L * 2.544 = <u>56.99 L H2O</u>

5 0
3 years ago
What is the wavelength (in nm) of
LenKa [72]

Answer:

λ = 0.45×10⁻⁶ m

Explanation:

Given data:

Wavelength of blue light = ?

Frequency of blue light = 6.69×10¹⁴ s⁻¹

Solution:

Formula;

Speed of wave = wavelength × frequency

Speed of wave = 3.00×10⁸ m/s

by putting vales,

3.00×10⁸ m/s = λ × 6.69×10¹⁴ s⁻¹

λ = 3.00×10⁸ m/s / 6.69×10¹⁴ s⁻¹

λ = 0.45×10⁻⁶ m

6 0
3 years ago
A compound accepts electrons from another substance to form a covalent bond. Which term best describes this
matrenka [14]

Answer:

A

Explanation:

3 0
3 years ago
Read 2 more answers
Severus Snape explains that if you have the molar mass of a compound and the empirical formula of a compound you can determine t
KengaRu [80]

Answer:

The molecular formula of the compound :C_4H_6O_2

Explanation:

The empirical formula of the compound =C_2H_3O

The molecular formula of the compound =C_{2n}H_{3n}O_n

The equation used to calculate the valency is :

n=\frac{\text{molecular mass}}{\text{empirical mass}}

We are given:

Mass of molecular formula = 86 g/mol

Mass of empirical formula = 43 g/mol

Putting values in above equation, we get:

n=\frac{86g/mol}{43g/mol}=2

The molecular formula of the compound :

C_{2\times 2}H_{3\times 2}O_2=C_4H_6O_2

7 0
2 years ago
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