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DedPeter [7]
3 years ago
5

C. Another radioisotope of americium exists which has an atomic mass of 242.

Chemistry
1 answer:
ollegr [7]3 years ago
7 0

Answer:

1 g  

Explanation:

The half-life of Am-242 (16 h) is the time it takes for half of it to disappear.

We can make a table of the mass left after each half-life.

\begin{array}{cccc}\textbf{No. of} & & \textbf{Percent} & \textbf{Mass}\\\textbf{Half-lives} & \textbf{Time/h} & \textbf{Remaining} & \textbf{Remaining/g}\\0& 0 & 100 & 8\\1 & 16 &50 & 4\\2 & 32 & 25 & 2\\3 & 48 & 12.5 & 1\\4 & 64 & 6.25 & 0.5\\\end{array}

The mass remaining after 48 h  is 1 g.

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Answer:

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6 0
3 years ago
The reaction a(g)⇌b(g) has an equilibrium constant of 5.8 and under certain conditions has q = 336. part a what can you conclude
Vika [28.1K]

Answer:

The answer is "As Q=336, at high-temperature \Delta G_{rxn}>0 and WhenK>1,\Delta G^{\circ}_{rxn}>0."

Explanation:

The equation for the reaction is:

A(g) \leftrightharpoons  B(g)  

K=5.8\\\\Q=336

At equilibrium,

\Delta G^{\circ}_{rxn}>0=-RT \ln \ K

When k=5.8(>1), the value of \ln k would be positive

So, \Delta G^{\circ}_{rxn} is negative (< 0)

So if K > l, \Delta G^{\circ}_{rxn}

If the reaction is not in equilibrium so the equation is :

\Delta G_{rxn}>0=\Delta G^{\circ}_{rxn}+RT \ln Q

Substituting the expression:

\Delta G_{rxn}>0= (-RT \ln K) + RT \ln  Q

                 = RT(\ln Q- \ln K)\\= RT(\ln (336)-\ln (5.8))\\= RT(4.06)

It is the positive value for all temperatures.

So, As Q = 336, at the high temperature \Delta G_{rxn}>0.

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5NH4OH

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<em><u /></em>

5NH4OH means 5 molecules (or moles) of NH4OH.  But the question asks per chemical formula, so 5 is correct,

There would be 5x4 or 20 atoms of H is 5 molecules of NH4OH.

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