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maks197457 [2]
3 years ago
11

If nothing is faster than light, how did the dark get there first? O.o

Physics
2 answers:
Arte-miy333 [17]3 years ago
7 0

Answer:

Nothing is faster than light. Dark is the absence of light, or indeed anything at all.  Darkness came before light, so light had to be created to get there. It's like turning on s flashlight in a dark room: the darkness is already there, and an outside source (you/the flashlight) needs to create light.

Explanation: Nothing is faster than light lighting is very fast.

erastova [34]3 years ago
4 0
Nothing is faster than light. Dark is the absence of light, or indeed anything at all. ... Darkness came before light, so light had to be created to get there. It's like turning on s flashlight in a dark room: the darkness is already there, and an outside source (you/the flashlight) needs to create light.
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A flat circular plate of copper has a radius of 0.262 m and a mass of 61.5 kg.
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0.031 m

Explanation:

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m = Mass of plate = 61.5 kg

v = Volume of plate = Volume of cylinder = πr²h

\rho=\frac{m}{v}\\\Rightarrow 8940=\frac{61.5}{\pi r^2h}\\\Rightarrow h=\frac{61.5}{\pi 0.262^2\times 8940}\\\Rightarrow h=0.031\ m

So, thickness of plate is 0.031 m

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4 years ago
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3 years ago
A car with a mass of 1.50 X 10^3 kg starts from rest and accelerates to a speed of 18.0 m/s in 12.0 s. Assume that the force of
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The average power is 20.3 kW

Explanation:

First of all, we calculate the work done on the car: the work-energy theorem states that the work done on the car is equal to the change in kinetic energy of the car, so we have

W=K_f - K_i = \frac{1}{2}mv^2-\frac{1}{2}mu^2

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W is the work done

K_i, K_f are the initial and final kinetic energy of the car

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Substituting,

W=\frac{1}{2}(1500)(18)^2=2.43\cdot 10^5 J

Now we can find the average power developed by the car's engine, which is given by

P=\frac{W}{t}

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Substituting,

P=\frac{2.43\cdot 10^5 J}{12.0}=20,250 W = 20.3 kW

Learn more about power:

brainly.com/question/7956557

#LearnwithBrainly

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4 years ago
What is the concentration of a solution if 65 g of sugar is dissolved into 200 ml of water?
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hope this helps

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