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maks197457 [2]
3 years ago
11

If nothing is faster than light, how did the dark get there first? O.o

Physics
2 answers:
Arte-miy333 [17]3 years ago
7 0

Answer:

Nothing is faster than light. Dark is the absence of light, or indeed anything at all.  Darkness came before light, so light had to be created to get there. It's like turning on s flashlight in a dark room: the darkness is already there, and an outside source (you/the flashlight) needs to create light.

Explanation: Nothing is faster than light lighting is very fast.

erastova [34]3 years ago
4 0
Nothing is faster than light. Dark is the absence of light, or indeed anything at all. ... Darkness came before light, so light had to be created to get there. It's like turning on s flashlight in a dark room: the darkness is already there, and an outside source (you/the flashlight) needs to create light.
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A student releases a marble from the top of a ramp. The marble increases
Fed [463]

Answer:

Vf = 69.56 cm/s

Explanation:

In order to find the final speed of the ramp, we will use the equations of motion. First we use second equation of motion to find out the acceleration of marble:

s = Vi t + (1/2)at²

where,

s = distance traveled = 160 cm

Vi = Initial Speed = 0 cm/s (since, marble starts from rest)

t = time interval = 4.6 s

a = acceleration = ?

Therefore,

160 cm = (0 cm/s)(4.6 s) + (1/2)(a)(4.6 s)²

a = (320 cm)/(4.6 s)²

a = 15.12 cm/s²

Now, we use first equation of motion:

Vf = Vi + at

Vf = 0 cm/s + (15.12 cm/s²)(4.6 s)

<u>Vf = 69.56 cm/s</u>

7 0
3 years ago
A sled that has a mass of 8 kg is pulled at a 50 degree angle with a force of 20 N. The force of friction acting on the sled is
vitfil [10]

The acceleration of the sled will be 1.30 m/s². Force is defined as the product of mass and acceleration.

<h3>What is force?</h3>

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

Given data;

m(mass of sled)=8 kg

Θ is the inclination of force= 50°

Force of friction,f=2.4 N.

The applied force at the given angle is resolved into the two-component as;

\rm F_h=F cos \theta \\\\ F_h= 20 cos 50 ^0 \\\\ F_h= 12.85 \ N

\rm F_v=F sin \theta \\\\  F_v=20 sin 50^0 \\\\   F_v=15.32 \ N

The net vertical force is zero;

\rm F_N=mg-Fsin50^0 \\\\ \rm F_N=8 \times 9.81 -15.32 \\\\ F_N=63.1 \ N \\\\

From Newton's second law the net force as;

\rm \sum F_{net}=ma \\\\ Fcos 60^0-f =ma \\\\ a=\frac{12.855-2.4}{8} \\\\a = 1.30 \ m/s^2

Hence, the acceleration of the sled will be 1.30 m/s².

To learn more about the force refer to the link;

brainly.com/question/26115859

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5 0
2 years ago
Read 2 more answers
1. li took 2 } seconds for a car's vclocity to change from 20 m/s to 15 m/s. The mass of the car was 1370 kg. What force was req
Pani-rosa [81]

Answer:

Do you still need help??

Explanation:

3 0
3 years ago
The angle between incident ray and reflected ray is 130.what is the value of angle of incidence​
Artyom0805 [142]

Answer:

65

Explanation:

as i = r , so i + i = 130

so , i = 130/2 =65

7 0
3 years ago
Read 2 more answers
7. How long does it take a ball rolling down a hill to change its speed from 3 m/sec to 34.5 m/sec
lys-0071 [83]

The time elapsed is 9 seconds

Explanation:

The motion of the ball is a uniformly accelerated motion (a motion with constant acceleration), so we can use the following suvat equation:

v=u+at

where :

v is the final velocity  of the ball

u is the initial velocity

a is the acceleration

t is the time  elapsed

For the ball in this problem, we have:

u = 3 m/s is the initial velocity

v = 34.5 m/s is the final velocity

a=3.5m/s^2 is the acceleration

Solving for t, we find the time taken for this change in velocity:

t=\frac{v-u}{a}=\frac{34.5-3}{3.5}=9 s

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3 years ago
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