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3 years ago

How many atoms are in 4 Al2(SO3)3

Chemistry

1 answer:

scZoUnD [109]3 years ago

4 0

There are 337.23 × 10²³ atoms in 4 moles of aluminum sulfite Al₂(SO₃)₃.

Explanation:

The questions ask how many atoms are in 4 moles of aluminum sulfite Al₂(SO₃)₃?

To answer this we use the Avogadro's number to devise the following reasoning:

if in 1 mole of Al₂(SO₃)₃ there are 14 × 6.022 × 10²³ atoms

then in 4 moles of Al₂(SO₃)₃ there are X atoms

X = (4 × 14 × 6.022 × 10²³) / 1 = 337.23 × 10²³ atoms

Learn more about:

Avogadro's number

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3 years ago

What are the answers to the blanks to make this equation balanced

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3 years ago

An ice cube tray full of water is put into a freezer. Which energy change occurs in the particles in the water as it undergoes a

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2 years ago

If ch4 and c4h8 are released simultaneously at ends of a 50.0cm long glass tube, at what distance from the left end of the tube

Keith_Richards [23]

Answer:

They meet at the distance of 32.5 cm

Explanation:

The rate of diffusion is inversely proportional to the molar mass of gases.

If diffusion is represented as d and mass of gases as M. Then , rate is given as:

$d=k\sqrt{\frac{1}{M}}$

For , two gases

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{M_{2}}{M_{1}}}$

First , Calculate the ,molar mass of each gas :

CH4 = 1 (mass of C) + 4(mass of H)

= 1(12)+4(1)

= 12 + 4 = 16 gram

M1 = 16 gram

C4H8 = 4(mass of C) + 8(Mass of H)

= 4(12) + 8(1)

= 48 + 8

M2 = 56 grams

d1 is diffusion of CH4

d2 = diffusion of C4H8

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{M_{2}}{M_{1}}}$

$\frac{d_{1}}{d_{2}}=\sqrt{\frac{56}{16}$ }

$\frac{d_{1}}{d_{2}} = 1.87$

This means CH4 diffuse 1.87 times faster than C4H8

Now, the mathematical part

If velocity of C4H8 = 1 cm/sec , then velocity of CH4 = 1.87 cm/sec

v1 = 1.87 cm/sec

v2 = 1 cm/sec

Let both meet at time "t". If distance travelled by CH4(s1) = x , then remaining(s2) distance (50-x) is travelled by C4H8

(see the attached image)

$time =\frac{distance}{speed}$

since both meet at same time so t = constant.

$\frac{s1}{v1}=\frac{s2}{v2}$

$\frac{x}{1.87}\frac{50-x}{1.00}$

on solving for x we get,

x = 17.42 cm

from the other side the distance is (50 - x)

= 50 - 17.42 = 32.5 cm

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3 years ago