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soldier1979 [14.2K]
3 years ago
15

How many atoms are in 4 Al2(SO3)3

Chemistry
1 answer:
scZoUnD [109]3 years ago
4 0

There are 337.23 × 10²³ atoms in 4 moles of aluminum sulfite Al₂(SO₃)₃.

Explanation:

The questions ask how many atoms are in 4 moles of aluminum sulfite Al₂(SO₃)₃?

To answer this we use the Avogadro's number to devise the following reasoning:

if in        1 mole of Al₂(SO₃)₃ there are 14 × 6.022 × 10²³ atoms

then in  4 moles of Al₂(SO₃)₃ there are X  atoms

X = (4 × 14 × 6.022 × 10²³) / 1 = 337.23 × 10²³ atoms

Learn more about:

Avogadro's number

brainly.com/question/13848085

brainly.com/question/13842198

#learnwithBrainly

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Answer:

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There are two naturally occurring isotopes of boron. 10 B has a mass of 10.0129 u. 11 B has a mass of 11.0093 u. Determine the a
Vanyuwa [196]
<h2>Natural Abundance for 10B is 19.60%</h2>

Explanation:

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For calculation of abundance of both the isotopes -

Supposing it was 50/50, the average mass would be 10.5, so to increase the mass we need a more percentage of 11.

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