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Solnce55 [7]
3 years ago
9

A 50,000 kg train car moving at 2 m/s collides and connects to another identical car initially at rest.

Physics
1 answer:
stich3 [128]3 years ago
6 0

Complete question:

A 50,000 kg train car moving at 2 m/s collides and connects to another identical car initially at rest. Find the velocity of the two cars immediately after collision.

Answer:

The final velocity of the two cars after collision is 1 m/s.

Explanation:

Given;

mass of first car, m₁ = 50,000 kg

mass of the second car, m₂ = 50,000 kg  (identical to first car)

initial velocity of the first car, u₁ = 2 m/s

initial velocity of the second car, u₂ = 0

let the final velocity of the two cars after collision = v

The final velocity of the two cars can be calculated from law of conservation of linear momentum for inelastic collision.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

50,000 x 2    + 50,000 x 0 = v(50,000 + 50,000)

100,000 = 100,000v

v = 100,000 / 100,000

v = 1 m/s

Therefore, the final velocity of the two cars after collision is 1 m/s.

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Learning Task 2:
swat32

Answer:

Hello your question has some missing parts attached below is the missing part

Answer :

  1. Caused severe damage  ( 7 )  ----- E
  2. Furniture moves ( 5 ) -------- G
  3. May not be felt ( 2 ) ---------- F
  4. Felt by most people ( 4 ) --------- D
  5. widespread destruction ( 8 up ) ------ B
  6. lead to a lot of damage ( 6 ) -------- A
  7. Felt little by people ( 3 ) ---------- C

Explanation:

Matching the Richter magnitude indicated in column A with the Earthquake effect found in column B

  1. Caused severe damage  ( 7 )  ----- E
  2. Furniture moves ( 5 ) -------- G
  3. May not be felt ( 2 ) ---------- F
  4. Felt by most people ( 4 ) --------- D
  5. widespread destruction ( 8 up ) ------ B
  6. lead to a lot of damage ( 6 ) -------- A
  7. Felt little by people ( 3 ) ---------- C

7 0
3 years ago
An RC circuit takes t = 2.5 ms to charge to 35% of its full charge after it weas connected to a battery, What is the total time
marin [14]

Answer: time taken to charge to 95%

t = -5.80[ln(1-0.95)]

t = 17.38ms

Explanation:

For an RC Charging circuit

Where Vs

Vc = Vs (1 - e^(-t/RC))

Vc/Vs = 1 - e^(-t/RC)

-t/RC = ln(1 - Vc/Vs)

t = -RC[ln(1 - Vc/Vs)] and RC = k = -t/ln(1 - Vc/Vs)

Where ;

Vc = voltage across the capacitor

Vs = voltage supply

t = charging time = 2.5ms

k = RC = time constant.

Vc/Vs = 0.35

To calculate the time constant k;

k = -t/ln(1- Vc/Vs)

k = -2.5/ln(1-0.35)

k = 5.80ms

time taken to charge to 95%

t = -5.80[ln(1-0.95)]

t = 17.38ms

4 0
3 years ago
El tubo de entrada que suministra presión de aire para operar un gato hidráulico tiene 2 cm de diámetro. El pistón de salida es
Bess [88]

Answer:

La presión neumática para levantar un automóvil de 17,640 newtons es 220,500 pascales.

Explanation:

Asumiendo que la presión (P), medida en pascales, tiene una distribución uniforme sobre la superficie del pistón, se calcula a partir de la siguiente expresion:

P = \frac{F}{A}

Donde:

F - Fuerza motriz, medida en newtons.

A - Área del pistón, medida en metros cuadrados.

La fuerza motriz es equivalente al peso del automóvil. El área del pistón (A), medido en metros cuadrados, es determinado por:

A=\frac{\pi}{4}\cdot D^{2}

Donde D es el diámetro del pistón, medido en metros.

Si D = 0.32\,m y F =17,640\,N, entonces la presión neumática es:

A = \frac{\pi}{4}\cdot (0.32\,m)^{2}

A \approx 0.080\,m^{2}

P = \frac{17,640\,N}{0.080\,m^{2}}

P = 220,500\,Pa

La presión neumática para levantar un automóvil de 17,640 newtons es 220,500 pascales.

8 0
3 years ago
An object on a number line moved from x = 15 cm to x = 165 cm and then
olasank [31]

Answer:

v_avg = 2.9 cm/s

Explanation:

The average velocity of the object is the sum of the distance of all its trajectories divided the time:

v_{avg}=\frac{x_{all}}{t}

x_all is the total distance traveled by the object. In this case you have that the object traveled in the first trajectory 165cm-15cm = 150cm, and in the second one, 165cm - 25cm = 140cm

Then, x_all = 150cm + 140cm = 290cm

The average velocity is, for t = 100s

v_{avg}=\frac{290cm}{100s}=2.9\frac{cm}{s}

hence, the average velocity of the object in the total trajectory traveled is 2.9 cm/s

3 0
3 years ago
Read 2 more answers
Calculate the potential energy of a rock that has a 45 kg mass and is sitting
Montano1993 [528]

Answer:

P.E = 13230 J

Explanation:

Given,

The mass of the rock, m = 45 Kg

The rock is sitting at a height from the ground, h = 30 m

The acceleration due to gravity, g = 9.8 m/s²

The potential energy of the body is given by the formula,

                            P.E = mgh joules

Substituting the given values in the above equation

                             P.E = 45 x 9.8 x 30

                                   = 13230 J

Hence, the potential energy of the rock is P.E = 13230 J

6 0
3 years ago
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