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Solnce55 [7]
3 years ago
9

A 50,000 kg train car moving at 2 m/s collides and connects to another identical car initially at rest.

Physics
1 answer:
stich3 [128]3 years ago
6 0

Complete question:

A 50,000 kg train car moving at 2 m/s collides and connects to another identical car initially at rest. Find the velocity of the two cars immediately after collision.

Answer:

The final velocity of the two cars after collision is 1 m/s.

Explanation:

Given;

mass of first car, m₁ = 50,000 kg

mass of the second car, m₂ = 50,000 kg  (identical to first car)

initial velocity of the first car, u₁ = 2 m/s

initial velocity of the second car, u₂ = 0

let the final velocity of the two cars after collision = v

The final velocity of the two cars can be calculated from law of conservation of linear momentum for inelastic collision.

m₁u₁ + m₂u₂ = v(m₁ + m₂)

50,000 x 2    + 50,000 x 0 = v(50,000 + 50,000)

100,000 = 100,000v

v = 100,000 / 100,000

v = 1 m/s

Therefore, the final velocity of the two cars after collision is 1 m/s.

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Answer:

False. This is because ellipses have 2 focus points and not only one.

6 0
2 years ago
Which is NOT a part of the Kinetic Molecular Theory? A) Atoms are in constant motion B) Gases are more compressible than liquids
djverab [1.8K]
The best answer would be the second option B) because that is NOT part of the Kinetic Molecular Theory.
5 0
3 years ago
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A diesel engine does not use spark plugs to ignite the fuel and air in the cylinders. Instead, the temperature required to ignit
Klio2033 [76]

Answer:

Compression ratio = 24.42

Explanation:

From Thermodynamic,

Adiabatic Equation ⇒ TV^{γ-1} = Constant.

⇒T₁V₁^{γ-1}  = T₂V₂^{γ-1} ..................(1)

Where T₁= initial Temperature, V₁ = Initial Volume, T₂ = final Temperature, V₂ = Final Volume.

Given:  T₁= 18°C we convert to  Kelvin(K) by adding 273.

∴      T₁= 18°C + 273 = 291K

        T₂ = 733° C  also,we convert to  Kelvin(K) by adding 273

 ∴      T₂ = 733° C +273 =1046K

          γ = 7/5

 ∴ Rearranging equation(1), we have

    (T₁/T₂) = (V₂/V₁)^{γ-1}................(2)

also rearranging equation(2) we have

   (V₁/V₂)^{γ-1} = (T₂/T₁).

Where (V₁/V₂) = Compression ratio.

∴ (V₁/V₂)^{(7/5)-1} =( 1046/291)

simplifying the index in the equation

I.e (7/5)-1 = (7-5 )/5 = 2/5.

(V₁/V₂)^2/5 =(1046/291)^2/5

Multiplying the power on both side of the equation by 5/2.

∴(V₁/V₂)^(2/5)×(5/2) = (1046/291)^(5/2)

⇒ V₁/V₂= (1046/291)^2.5=( 3.59)^2.5

    V₁/V₂ = 24.42.

∴ Compression ratio = 24.42

7 0
3 years ago
An airplane in the process of taking off travels with a speed of 80 m/s at an angle of 15° above the horizontal. What is the gro
9966 [12]

Answer:

Option C

Explanation:

given,

velocity of airplane = 80 m/s

angle with the horizontal = 15°

speed of the ground= ?

when the plane is taking off the horizontal component of the velocity is v cosθ

so,      

        ground speed of the airplane is = v\times cos\theta

                                                              = 80 \times cos 15^0

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horizontal velocity of the air plane comes out to be 77.27 m/s ≅ 77 m/s

so, the correct option is Option C

5 0
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4   Not prohibiting the riders to sit on gunwales, transom, stern, sides, bow or decking over the bow sides when the boat is underway, except when sufficient guards or railings are provided

5   Operating the boat or giving permission to other people to operate the boat while drunk or under illegal substances

6   Operating the boat and the wash or wake endanger any property or person

7   Operating the boat in an area designated for swimming

8   Operating the boat beyond a slow, no wake speed in locations marked as no wake zones

 

We can see that in this case, the rule # 6 is being trespassed. Therefore under Minnesota Boating Laws, we have committed an Illegal Operating Practice.

8 0
3 years ago
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