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katrin [286]
3 years ago
11

PLEASE HELP!! 10 POINTS! what could the fourth quantum number of a 2s^2 electron be?

Chemistry
2 answers:
Tom [10]3 years ago
7 0

Answer: ms = +1/2

Explanation: a pex

mrs_skeptik [129]3 years ago
5 0

Answer:

D. ms=+1/2.

Explanation:

Hello there!

In this case, since the quantum numbers are known as:

* Principal quantum number (n) which cannot be zero. The allowed values of n are therefore 1, 2, 3, 4, and so on.

* Angular quantum number (l) is able to be any integer between 0 and n-1. If n = 2, for example, l can be either 0 or 1.

* Magnetic quantum number (m) is able to be any integer between -l and +l. If l = 3, m can be either -3, -2, -1, 0, +1, +2 or +3.

* Spin Quantum Number (ms): ms = +½ or -½. Accounts for the orientation of the spin axis of an electron as it is able to spin in only one of two directions.

Thus, since the fourth quantum number is ms, spin, we infer that the answer is D. ms=+1/2 because it represents the positive spin on 2s^2.

Best regards!

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5.4 tonnes.

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What is the density in g/L of gas with a molar mass of 2.016 g/mol at 4.77 atm and 118k?
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Need help I don’t understand this at all need to show my work and strategy it’s stoichiometry gram to gram please help
laila [671]

Answer:

781×10¯² g of MgCl₂.

Explanation:

The balanced equation for the reaction is given below:

Mg + 2HCl —> MgCl₂ + H₂

Next, we shall determine the mass of HCl that reacted and the mass of MgCl₂ produced from the balanced equation. This is illustrated below:

Molar mass of HCl = 1 + 35.5

= 36.5 g/mol

Mass of HCl from the balanced equation = 2 × 36.5 = 73 g

Molar mass of MgCl₂ = 24 + (35.5×2)

= 24 + 71

= 95 g/mol

Mass of MgCl₂ from the balanced equation = 1 × 95 = 95 g

SUMMARY:

From the balanced equation above,

73 g of HCl reacted to produce 95 g of MgCl₂.

Finally, we shall determine the mass of MgCl₂ produced by the reaction of 6 g of HCl. This can be obtained as follow:

From the balanced equation above,

73 g of HCl reacted to produce 95 g of MgCl₂.

Therefore, 6 g of HCl will react to produce = (6 × 95)/73 = 781×10¯² g of MgCl₂.

Thus, 781×10¯² g of MgCl₂ were obtained from the reaction.

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