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baherus [9]
3 years ago
13

What are the transfer of energy for the 6 simple machine? Ex: inclined plane is gravitational potential energy to mechanical ene

rgy. What are the rest?
Engineering
1 answer:
lilavasa [31]3 years ago
8 0

Answer:

I. Inclined plane: GPE to KE.

II. Screw: KE to GPE.

III. Wheel and axle: GPE to KE.

IV. Lever: GPE to KE.

V. Wedge: GPE to KE.

VI. Pulley: GPE to KE.

Explanation:

A simple machine can be defined as a type of machine with no moving parts but can be used to perform work.

Basically, a simple machine allows for the transformation of energy into work. The six simple machines are;

I. <u>Inclined plane</u>: gravitational potential energy to mechanical energy (kinetic energy). It is set at an angle and then used to lift an object.

II. <u>Screw</u>: kinetic energy to potential energy. It is held in position and then used to tighten two or more objects together.

III. <u>Wheel and axle</u>: gravitational potential energy to mechanical energy (kinetic energy). It comprises of two circular objects which aids in the motion of an object such as a car.

IV. <u>Lever</u>: gravitational potential energy to mechanical energy (kinetic energy). It comprises of a pivoted bar at a fixed point (fulcrum) that allows it to be used for lifting heavy objects.

V. <u>Wedge</u>: gravitational potential energy to mechanical energy (kinetic energy). It can be used to split objects into halves.

VI. <u>Pulley</u>: gravitational potential energy to mechanical energy (kinetic energy). It is made up of a wheel and rope which allows force to be multiplied such as in a drawing well.

Energy can be defined as the ability (capacity) to do work. The two (2) main types of energy are;

a. Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.

b. Kinetic energy (KE): it is an energy possessed by an object or body due to its motion.

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Answer:

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Explanation:

Given;

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W_f = \frac{C_g - C_0}{C_g -C_f} \\\\W_f =\frac{100 - 3.1}{100-0}\\\\W_f = 0.969\\\\\\W_g = \frac{C_0 - C_a}{C_g -C_f} \\\\W_g =\frac{3.1-0}{100-0}\\\\W_g = 0.031

Determine the volume fraction;

V = \frac{W_g/ \rho_g}{W_f / \rho_f \ + \ W_g / \rho_g} *100 \%\\\\V = \frac{0.031/ 2.3}{0.969 / 7.9 \ + 0.031 / 2.3}*100\%\\\\V = 9.9\%

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3 years ago
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Answer: 133.88 MPa approximately 134 MPa

Explanation:

Given

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Critical internal crack length, l' = 6 mm = 6*10^-3 m

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112 MPa = 26 MPa / Y.√[3.142 * 8.6*10^-3)/2]

112 MPa = 26 MPa / Y.√(3.142 * 0.043)

112 = 26 / Y.√1.35*10^-2

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σ = 26 / 2 * [√3.142 * (6*10^-3/2)]

σ = 26 / 2 * √(3.142 *3*10^-3)

σ = 26 / 2 * √0.009426

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