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baherus [9]
2 years ago
13

What are the transfer of energy for the 6 simple machine? Ex: inclined plane is gravitational potential energy to mechanical ene

rgy. What are the rest?
Engineering
1 answer:
lilavasa [31]2 years ago
8 0

Answer:

I. Inclined plane: GPE to KE.

II. Screw: KE to GPE.

III. Wheel and axle: GPE to KE.

IV. Lever: GPE to KE.

V. Wedge: GPE to KE.

VI. Pulley: GPE to KE.

Explanation:

A simple machine can be defined as a type of machine with no moving parts but can be used to perform work.

Basically, a simple machine allows for the transformation of energy into work. The six simple machines are;

I. <u>Inclined plane</u>: gravitational potential energy to mechanical energy (kinetic energy). It is set at an angle and then used to lift an object.

II. <u>Screw</u>: kinetic energy to potential energy. It is held in position and then used to tighten two or more objects together.

III. <u>Wheel and axle</u>: gravitational potential energy to mechanical energy (kinetic energy). It comprises of two circular objects which aids in the motion of an object such as a car.

IV. <u>Lever</u>: gravitational potential energy to mechanical energy (kinetic energy). It comprises of a pivoted bar at a fixed point (fulcrum) that allows it to be used for lifting heavy objects.

V. <u>Wedge</u>: gravitational potential energy to mechanical energy (kinetic energy). It can be used to split objects into halves.

VI. <u>Pulley</u>: gravitational potential energy to mechanical energy (kinetic energy). It is made up of a wheel and rope which allows force to be multiplied such as in a drawing well.

Energy can be defined as the ability (capacity) to do work. The two (2) main types of energy are;

a. Gravitational potential energy (GPE): it is an energy possessed by an object or body due to its position above the earth.

b. Kinetic energy (KE): it is an energy possessed by an object or body due to its motion.

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For the following conditions determine whether a CMFR or a PFR is more efficient in removing a reactive compound from the waste
andrew11 [14]

Answer:

The PFR is more efficient in the removal of the reactive compound as it has the higher conversion ratio.

Xₚբᵣ = 0.632

X꜀ₘբᵣ = 0.5

Xₚբᵣ > X꜀ₘբᵣ

Explanation:

From the reaction rate coefficient, it is evident the reaction is a first order reaction

Performance equation for a CMFR for a first order reaction is

kτ = (X)/(1 - X)

k = reaction rate constant = 0.05 /day

τ = Time constant or holding time = V/F₀

V = volume of reactor = 280 m³

F₀ = Flowrate into the reactor = 14 m³/day

X = conversion

k(V/F₀) = (X)/(1 - X)

0.05 × (280/14) = X/(1 - X)

1 = X/(1 - X)

X = 1 - X

2X = 1

X = 1/2 = 0.5

For the PFR

Performance equation for a first order reaction is given by

kτ = In [1/(1 - X)]

The parameters are the same as above,

0.05 × (280/14) = In (1/(1-X)

1 = In (1/(1-X))

e = 1/(1 - X)

2.718 = 1/(1 - X)

1 - X = 1/2.718

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X = 1 - 0.3679

X = 0.632

The PFR is evidently more efficient in the removal of the reactive compound as it has the higher conversion ratio.

3 0
3 years ago
What is the composition, in atom percent, of an alloy that consists of 4.5 wt% Pb and 95.5 wt% Sn?
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Answer: Option A is correct -- 2.6 at% Pb and 97.4 at% Sn.

Explanation:

Option A is the only correct option -- 2.6 at% Pb and 97.4 at% Sn. While option B, which is 7.6 at% Pb and 92.4 at% Sn. and option C, which is 97.4 at% Pb and 2.6 at% Sn. and option D, which is 92.4 at% Pb and 7.6 at% Sn. are wrong.

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Answer:

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The code is extracted from the Question and completed after extraction.

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Answer:

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