Answer:
A. Constructive
B. Destructive
C. Destructive
D. Constructive
Explanation:
Constructive interference takes place at locations along the path of two superposed waves where the waves are in phase such that a high or low point of one of the waves corresponds with a high or low point of the other wave which gives a resulting wave amplitude which is the sum of the amplitudes of the individual waves
Destructive interference takes place at locations along the path of two superposed waves where one wave is out of phase with the other wave such that a high or low point of one of the waves coincides with a low or high point of the other wave respectively thereby cancelling the effect of the other wave and giving a resulting wave that has an amplitude which is the difference in the amplitudes of the individual waves
Therefore;
At point A, the peak of each wave partially coincides resulting in constructive interference
At point B, the peak of the blue wave and the trough of the red wave partially coincides resulting in destructive interference
At point C, the through of the blue wave and the peak of the back wave partially coincides resulting in destructive interference
At point D, the trough of each wave partially coincides resulting in constructive interference.
Kinetic friction happens when there is kinetic energy and it is coming into contact with another source. ex: a ball rolling.
I think you would use F = ma
F = 65*10
F = 650N
(The 10m/s is from acceleration due to gravity)
Answer:
As given that the car maintains a constant speed v as it traverses the hill and valley where both the valley and hill have a radius of curvature R.
(i) At point C, the normal force acting on the car is largest because the centripetal force is up. gravity is down and normal force is up. net force is up so magnitude of normal force must be greater than the car's weight.
(ii) At point A, the normal force acting on the car is smallest because the centripetal force is down. gravity is down and normal force is up. net force is up so magnitude of normal force must be less than car's weight.
(iii) At point C, the driver will feel heaviest because the driver's apparent weight is the normal force on her body.
(iv) At point A, the driver will feel the lightest.
(v)The car can go that much fast without losing contact with the road at A can be determined as follow:
Fn=0 - lose contact with road
Fg= mv²/r
mg=mv²/r
v=sqrt (gr)
