Answer:
Explanation:
capacitance of sphere 2 will be 4.5 times sphere 1
a ) when spheres are in contact they will have same potential finally . So
V_1 / V_2 = 1
b )
Charge will be distributed in the ratio of their capacity
charge on sphere1 = q x 1 / ( 1 + 4.5 )
= q / 5.5
fraction = 1 / 5.5
c ) charge on sphere 2
= q x 4.5 / 5.5
fraction = 4.5 / 5.5
d ) surface charge density of sphere 1
= q /( 5.5 x A ) where A is surface area
surface charge density of sphere 2
= q x 4.5 /( 5.5 x 4.5² A ) where A is surface area
= q /( 5.5 x 4.5 A )
q_1/q_2 = 4.5
Answer:
![6.046N](https://tex.z-dn.net/?f=6.046N)
Explanation:
The net force exerted on the mass is the sum of tension force and the external force of gravity.
![F_n_e_t=F_g+F_t](https://tex.z-dn.net/?f=F_n_e_t%3DF_g%2BF_t)
is the tension force.
is the force of gravity.
![F_n_e_t=ma_c=mv^2/r\\](https://tex.z-dn.net/?f=F_n_e_t%3Dma_c%3Dmv%5E2%2Fr%5C%5C)
where
is the rope's radius from the fixed point.
From the net force equation above:
![F_t=F_n_e_t-F_g\\=mv^2/r-mg\\=0.4\times(8.5^2/2.9)-0.4\times9.8\\=6.046N](https://tex.z-dn.net/?f=F_t%3DF_n_e_t-F_g%5C%5C%3Dmv%5E2%2Fr-mg%5C%5C%3D0.4%5Ctimes%288.5%5E2%2F2.9%29-0.4%5Ctimes9.8%5C%5C%3D6.046N)
Hence the tension force is 6.046N
Answer:
Steel is almost 2.9 times heavier the aluminium.
Answer:
A
Explanation:
Hooke's law! F(spring)=-kx
There's no tricky square law here. The spring constant doesn't change, only x (distance stretched) changes. Therefore, if distance is halved, Force will be halved.