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irina1246 [14]
3 years ago
8

A car is going 8 meters per second on an access road into a highway

Physics
1 answer:
TiliK225 [7]3 years ago
3 0

Answer:

20.96 m/s^2 (or 21)

Explanation:

Using the formula (final velocity - initial velocity)/time = acceleration, we can plug in values and manipulate the problem to give us the answer.

At first, we know a car is going 8 m/s, that is its initial velocity.

Then, we know the acceleration, which is 1.8 m/s/s

We also know the time, 7.2 second.

Plugging all of these values in shows us that we need to solve for final velocity. We can do so by manipulating the formula.

(final velocity - initial velocity) = time * acceleration

final velocity = time*acceleration + initial velocity

After plugging the found values in, we get 20.96 m/s/s, or 21 m/s

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jonny [76]

Answer:

20.96 m/s

Explanation:

Apply the kinematic equation:

Vf=Vi+at

Vi=8m/s

a=1.8m/s^2

t=7.2s

Putting this all in should give you your answer of 12.96m/s

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3 years ago
Which electrode in Thomson’s vacuum tube was positively charged
Taya2010 [7]

Anode

Explanation:

The anode in the gas discharge tube used by Thomson in his experiment was the positively charged electrode.

Using the gas discharge tube, Thomson made the remarkable discovery of cathode rays.

The rays moves from the negatively charged cathode to the positively charged anode. This indicated that the rays carry positive charges.

Some parts of the tube are:

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Learn more:

cathode brainly.com/question/12747250

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while racing on a flat track, a car rounds a curve of 28m radius and instantaneously experiences a centripetal acceleration of 1
liubo4ka [24]
When a body strictly moves on a curve, it's velocity at a point is tangential to the curve at that point.

Centripetal acceleration is the acceleration that a body experiences by the virtue of change in it's tangential velocity. It is directed towards the centre and mathematically is v^2/R where v is the speed at the instant.

So, 18 = v^2/R
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A skier stands at the top of a 50 meter slope. He then skis down the slope. What is his approximate speed at the bottom of the s
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