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konstantin123 [22]
3 years ago
5

An impala is an African antelope capable of a remarkable vertical leap. In one recorded leap, a 45 kg impala went into a deep cr

ouch, pushed straight up for 0.21 s, and reached a height of 2.5 m above the ground.To achieve this vertical leap, with a. What force did the impala push down on the ground? Express your answer to two significant figures and include the appropriate units. b. What is the ratio of this force to the antelope's weight?
Physics
1 answer:
Elis [28]3 years ago
4 0

Answer:

(a) F = 1500 N.

(b) Ratio force to the antelepe's weight = 3.40

Explanation:

Force : This can be defined as the product of mass and the distance moved by a body. Its S.I unit is Newton. It can be represented mathematically as

F = Ma

Where F= force, M = mass (Kg) and a = Acceleration (m/s²)

Weight: This can be defined as the force on a body due to gravitation field. It is also measured in Newton (N). It can be represented mathematically as

W = Mg

Where W = weight of the body, M = mass of the body (Kg), g = Acceleration due to gravity.

(a)

F = Ma

Where M = 45kg,

a = unknown.

But we can look for acceleration Using one of the equation of motion,

v² = u² + 2gs

Where v= final velocity(m/s), u = initial velocity (m/s) g = 0 m/s, g = 9.8m/s² and s = height = 2.5m.

∴ v² = 2gs

 v = √2gs = √(2×9.8×2.5)

v= √49 = 7m/s

With the force applied, the impala’s velocity must increase from 0 m/s to 7 m/s in 0.21 second

∴ a = (v-u)/t

 a = (7-0)/0.21 = 7/0.21

  a = 33.33 m/s².

F = 45 × 33.33 ≈ 1500

F = 1500 N.

(b)

Where F = Force = 1500 N

and W = Weight = Mg = 45 × 9.8 = 441 N

∴Ratio force to the antelepe's weight = F/W = 1500/441 = 3.40

 Ratio force to the antelepe's weight = 3.40

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Answer:

time required is 6.72 years

Explanation:

Given data

mass m = 3.20 ✕ 10^7 kg

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power p = 2.96 kW  =2.96 × 10^3 J/s

to find out

time period

solution

we know work is mass × gravity force × height

and power is work / time

so we say that power =  mass  gravity force × height / time

now put all value and find time period

power =  mass × gravity force × height / time

2.96 × 10^3 =  3.20 ✕ 10^7  × 9.81× 2 × 10^3  / time

time =  62.784 × 10^10 / 2.96 × 10^3

time = 21.21081081 × 10^7 sec

time = 58.91891892 × 10^3 hours

time = 6.72 years

so time required is 6.72 years

3 0
3 years ago
A skier is accelerating down a 30.0-degree hill at 3.80 m/s^2.
Bond [772]

Answer:

ax = -3.29[m/s²]

ay = -1.9[m/s²]

Explanation:

We must remember that acceleration is a vector and therefore has magnitude and direction.

In this case, it is accelerating downwards, therefore for a greater understanding we will make a diagram of said vector, this diagram is attached.

a_{x}=-3.8*cos(30) = -3.29 [m/s^{2}]\\ a_{y}=-3.8*sin(30) = -1.9 [m/s^{2}]

3 0
3 years ago
a ball of mass 0.5 kg moving at 10 m/s collides with another ball of equal mass at rest. if the two balls move off together afte
nexus9112 [7]

Answer:

5 m/s

Explanation:

Here we can see there is no external force acted on a two masses when we consider the motion. If there is no external forces then momentum is conserved.

Initial momentum = Final momentum

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7 0
3 years ago
An acorn falls 10 meters in 4 seconds. What is its average velocity?
quester [9]

Answer:

Average velocity, V = 2.5m/s

Explanation:

Given the following data

Displacement = 10m

Time = 4secs

Average velocity can be defined as the rate of change in displacement with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, average velocity is given by the equation;

Velocity = \frac{displacement}{time}

V = \frac{d}{t}

Substituting into the above equation;

V = \frac{10}{4}

Average velocity, V = 2.5m/s

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2 years ago
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vovikov84 [41]

Answer:

3.6km South East

Explanation:

Displacement is the shortest distance between the starting point and the ending point and the direction it is displaced in. To calculate the displacement we can use the pythagoras theorem because the 3km East and the 2km south form the two shorter sides of a right angled triangle between the starting and ending points. So, the displacement is the length C of the triangle which we can calculate as follows:

Pythagoras Theorem:

a^2+b^2=c^2

(2)^2+(3)^2=c^(2)

4+9=c^2

Square root 13 = c

c=3.6km (1dp)

The total displacement is 3.6km and is in the approximate direction of South East (because he travelled east and south).

Hope this helped!

8 0
3 years ago
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