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Andreas93 [3]
2 years ago
5

The slope of a line parallel to the line who is the equation 2x + y = 6

Mathematics
1 answer:
Tanya [424]2 years ago
3 0

Answer:

-2

Step-by-step explanation:

Note that slope-intercept form looks like: y = mx + b

In this case, isolate the y. Note the equal sign, what you do to one side, you do to the other. Subtract 2x from both sides:

2x (-2x) + y = 6 (-2x)

y = -2x + 6

Note in the slope-intercept form: y = mx + b

y = y

m = slope

x = x

b = y-intercept

In this case, your slope is -2. All lines parallel to the given equation will also have a slope of-2.

~

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Distribute.

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FOIL:

First, Outside, Inside, and Last

a * a = a^2

a * 3 = 3a

8 * a = 8a

8 * -3 = - 24

a^2 + 11a - 24

Distributed Expression: a^2 + 11a - 24

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3 years ago
A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
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Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

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