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rjkz [21]
2 years ago
14

A proton moving eastward with a velocity of 5. 0 × 103 m/s enters a magnetic field of 0. 20 t pointing northward. what is the ma

gnitude and direction of the force that acts on the proton?
Physics
1 answer:
Serggg [28]2 years ago
6 0

The magnitude of the force is 1.6*10^-16 N. The direction of force is upward.

The definition of force is the push or pull that causes a massed object to change its velocity. Force is an external agent that has the power to alter a body's resting or moving position. It has a direction and a magnitude. The total amount of forces exerted on an object is referred to as the magnitude of force.

The strength of the force increases when all the force is pulling in the same direction. When force is exerted on an item from different angles, the force's strength reduces. The amount that encapsulates the force's strength is known as its magnitude.

To learn more about force please visit -
brainly.com/question/10645619
#SPJ4

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The answer is D. Isotopes.
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A person is attracted toward the centerof the earth by a 500 n gravitational force. the force with which the earth is attracted
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6 0
3 years ago
A small balloon is released at a point 150 feet away from an observer, who is on level ground. If the balloon goes straight up a
Elza [17]

Answer:

\dfrac{dz}{dt}=0.65\ ft/s

Explanation:

Given that

x= 150 ft

\dfrac{dy}{dt}= 7\ ft/s

y= 14 ft

From the diagram

z^2=x^2+y^2

When ,x= 150 ft and y= 14 ft

z^2=150^2+14^2

z=\sqrt{150^2+15^2}

z=150.74 ft

z^2=x^2+y^2

By differentiating with respect to time t

2z\dfrac{dz}{dt}= 2x\dfrac{dx}{dt}+2y\dfrac{dy}{dt}

z\dfrac{dz}{dt}= x\dfrac{dx}{dt}+y\dfrac{dy}{dt}

Here x is constant that is why

\dfrac{dx}{dt}=0

z\dfrac{dz}{dt}= y\dfrac{dy}{dt}

Now by putting the values in the above equation we get

150.74\times \dfrac{dz}{dt}=14\times 7

\dfrac{dz}{dt}=\dfrac{14\times 7}{150.74}\ ft/s

\dfrac{dz}{dt}=0.65\ ft/s

Therefore the distance between balloon and observer increasing with 0.65 ft/s.

5 0
3 years ago
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