<span>Answer:
Pb(NO3)2+2HCl=PbCl2+2HNO3
Step 2
Find # of moles of Pb
13.87g Pb(NO3)2 x 1 mol/331.22=.041875 mol Pb(NO3)2
Step 3
Use balanced equation to find weight of Pb(NO3)2
.041875mol Pb x 1 mol Cl2/1mol Pb x 70.90g/1 mol Cl2=2.9689g Cl2
.041875 mol Pb x 207.2/1mol Pb=8.6765g Pb
=11.65g</span>
Due to presence of impurities further purification is needed.
A further purification is needed of the final product because of the presence of impurities in the final product. Further purification can also be done in order to gain pure product. There are various ways and methods which can be used for the purification such as Sublimation, Crystallization, Distillation, Differential Extraction and Chromatography.
These methods can be used for further purification and helps in the extraction of pure solution of final product so we can conclude that due to presence of impurities further purification is needed.
Learn more: brainly.com/question/25799551
Answer:
P = 559.553 mmHg
Explanation:
Clasius-Clapeyron:
- Ln(P2/P1) = - ΔHv/R [ 1/T2 - 1/T1 ]
∴ P1 = 23.8 mmHg = 3.173 KPa
∴ T1 = 25°C ≅ 298 K
∴ ΔHv = 40.657 KJ/mol
∴ R = 8.314 E-3 KJ/K.mol
∴ T2 = 96°C ≅ 369 K
⇒ Ln P2/P1 = - (40.657 KJ/mol/8.314 E-3 KJ/K,mol) [(1/369 K) - (1/298 K) ]
⇒ Ln P2/P1 = - (4890.185 K) [ - 6.457 E-4 K-1 ]
⇒ Ln P2/P1 = 3.1575
⇒ P2/P1 = 23.511
⇒ P2 = (23.511)(3.173 KPa)
⇒ P2 = 74.601 KPa = 559.553 mmHg
<span>The concentration would remain at 2.0m. The problem states that 0 ml from the 2.0 m solution is diluted, therefore implying that none of it was diluted. Therefore, the level of concentration of the new solution would be the same as before.</span>
