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djyliett [7]
3 years ago
15

PLEASE HELP ASAP I'LL MARK BRAINLIEST

Chemistry
1 answer:
bogdanovich [222]3 years ago
4 0

Answer:

Its velocity was 7.8 km/s northward.

Explanation:

Because the meteor was only 45 m wide and was 27,700 km above Earth's surface it was not visible with the aid of a telescope.

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Why do hurricanes occur near the equator and not further North? Why do they
Leya [2.2K]

Answer:

the occur near the equator bc its- bc its warm and they get weak bc it slows them down

Explanation:

7 0
4 years ago
Can we use water as a solvent to obtain ethyl butyrate?
klio [65]

Answer:

yes but it depends

Explanation:

7 0
3 years ago
The unbalanced equation below shows the combustion of methane.
Ratling [72]
B. 1, 2, 1, 2. You balance the equation by making sure there are equal elements on both sides.
3 0
3 years ago
4P+ 5O2 -> P4O10
Ratling [72]
If 4 moles of P is used by 5 mole of O2
then....0.489 moles will be used by 5/4 × .489 = .611 moles of O2

so .611 moles

so if 4 moles of P is burnt , 1 mole of P4O10 is produced ....so for .489 moles...... .489/4=.122 moles !
so mass will be .122× 283.89 = 34.7 grams

so first ans is .611 moles and second is 34.7 grams !

if you have any problem regarding this , just comment !!!
4 0
3 years ago
Read 2 more answers
An unknown compound containing only C and H was burnt, yielding 10.2 g of CO2 and 6.3 g of H2O. With a molecular weight of about
Lisa [10]

Answer:

C_2H_6

Explanation:

Hello.

In this case, we can see that the mass of carbon of the unknown compound comes from the yielded mass of carbon dioxide, thus, we compute the moles of carbon as follows:

m_C=10.2gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1mol C}{1molCO_2}=0.232 molC

Moreover, the mass of hydrogen comes from the yielded water, therefore we can also compute the moles of water:

m_H=6.3gH_2O*\frac{1molH_2O}{18gH_2O}*\frac{2molH_2}{1molH_2O}  =0.7molH

Then, to find the subscripts in the empirical formula, we divide by the moles of carbon as the smallest:

C:\frac{0.232}{0.232}=1\\ \\H:\frac{0.7}{0.232}=3

Whose molar mass is:

M_{CH_3}=12+1*3=15g/mol

Thus, the ratio of the molecular formula to the empirical formula is:

\frac{30}{15}=2

Therefore, the molecular formula is twice the empirical formula:

C_2H_6

Which is actually ethane.

Regards.

3 0
3 years ago
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