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MatroZZZ [7]
3 years ago
6

I got 13.7 is that correct

Mathematics
1 answer:
Ghella [55]3 years ago
3 0

Answer:

The answer to your question is 10.5 in

Step-by-step explanation:

Data

First triangle

height = x

base = 7 in

Second triangle

height = 12 in

base = 8 in

Process

1.- Use proportions to solve this problem, relates the sides of a triangle with the same sides of the other triangle.

                                   \frac{x}{7} = \frac{12}{8}

2.- Multiply both sides by 7

                                7\frac{x}{7} = \frac{7(12)}{8}

3.- Simplify

                                 x = \frac{84}{8}

4.- Result

                                x = 10.5 in

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An angle measures 50° more than the measure of a supplementary angle. What is the measure of each angle?
anzhelika [568]

Answer:

65° and 115°

Step-by-step explanation:

let one angle be x then the other is x + 50

The sum of 2 supplementary angles = 180°, hence

x + x + 50 = 180

2x + 50 = 180 ( subtract 50 from both sides )

2x = 130 ( divide both sides by 2 )

x = 65

Thus the 2 angles are x = 65° and x + 50 = 65 + 50 = 115°


8 0
3 years ago
7x - 3x = 24
Debora [2.8K]
7x - 3x = 24
The 7x and the 3x are both like terms, so they can be combined. 7 - 3 is 4, so the equation turns into
4x = 24
Now, you want to get the x alone, so you divide both sides by 4 because it is the opposite of multiplication. 24 divided by 4 is 6, so
x = 6
4 0
2 years ago
Read 2 more answers
Which of the following is equal to log 6
slavikrds [6]
log_ab+log_ac=log_a(b\cdot c)\\\\log_ab-log_ac=log_a(b:c)\\\\log_ab^c=c\cdot log_ab


\boxed{a)\ log2+log3=log(2\cdot3)=log6}\\\\b)\ log2-log3=log(2:3)=log\frac{2}{3}\\\\c)\ 2log2+log3=log2^2+log3=log4+log3=log(4\cdot3)=log12\\\\d)\ 2log2-log3=log2^2-log3=log4-log3=log(4:3)=log\frac{4}{3}
3 0
3 years ago
Read 2 more answers
SOLVE FOR X TO THE NEAREST TENTH
Genrish500 [490]

Answer:

x = 8.8

Step-by-step explanation:

First, you have to solve the side length for the smaller triangle.

c= \sqrt{ a^{2} +b^{2} }\\c= \sqrt{5^{2}+4^{2}  } \\\\c=\sqrt{25+16} \\c=\sqrt{41} \\c= 6.4\\

Now for the bigger square.

c= \sqrt{ a^{2} +b^{2} \\}    \\c = \sqrt{6.4^{2} +6^{2} } \\c= \sqrt{40.96+36} \\c= \sqrt{ 76.96}\\c= 8.77\\

Rounded to the nearest tenth = 8.8

https://g.co/kgs/dg245M

I use this for my pythagorean theorem questions

5 0
2 years ago
<img src="https://tex.z-dn.net/?f=8-4x%5Csqrt%7B4%7D" id="TexFormula1" title="8-4x\sqrt{4}" alt="8-4x\sqrt{4}" align="absmiddle"
iren2701 [21]

Answer:

8-4xroo4= 8-4x*2

=8-8x

8(1-x)=0

x=1

Step-by-step explanation:

8 0
2 years ago
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