The flow rate is 17gtts/min.
<h3>What is the drug infusion rate?</h3>
- The rate of infusion (or dosing rate) in pharmacokinetics refers to the ideal rate at which a drug should be supplied to achieve a steady state of a fixed dose that has been shown to be therapeutically effective. This rate is not only the rate at which a drug is administered.
- The infusion volume is divided into drops, which is known as a drip-rate. The Drip Rate formula is as follows: Volume (mL) times time (h) equals drip-rate. A patient must get 1,000 mL of intravenous fluids over the course of eight hours.
- Infusion rates of 3–4 mg/kg per minute are advised by manufacturers to reduce rate-related adverse effects. Usually, the infusion lasts for several hours. Although not advised, rates exceeding 5 mg/kg per hour may be tolerated by some patients.
- If no negative reactions occur, the rate may be increased in accordance with the table every 30 minutes up to a maximum rate of 3 ml/kg/hour (not to exceed 150 ml/hour).
To find the flow rate is 17gtts/min:
Therefore, The flow rate is 17gtts/min.
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Answer:
Explanation:
I ASSUME you mean acceleration is 3 m/s²
v² = u² + 2as
s = (v² - u²) / 2a
s = (18² - 12²) / (2(3))
s = 30 m
to verify we can see that the acceleration time is
t = (18 - 12) / 3 = 2 s
s = 0 + 12(2) + ½(3)2² = 30 m
The acceleration would actually be 1.6 m/s^2. Acceleration= final velocity-initial velocity/time taken. When you do that formula it comes out to equal that.
Don't look now, but the question GIVES you the formula to use, and it GIVES you the numbers to plug into the formula.
The formula to use to find the distance covered by the sound is
<em>Speed = (distance) / (time)</em>
They also give you:
speed = 330 m/s
time = 0.40 second
Stuff the numbers into the formula:
330 m/s = (Distance) / (0.40 second)
Multiply each side by (0.40 second), and you get:
(330 m/s) / (0.4 second) = Distance
<em>825 meters = Distance</em>
Total resistance = voltage / current = 220 / 5 = 44 ohms .
Even one 176-ohm resistor is too much. The current through it is 1.25 A,
and more than one of them in series reduces the current even further.
Connecting them in <em><u>parallel</u></em>, however . . .
Four resistors of 176-ohms each, in <u>parallel</u>, have a net effective resistance
of 176/4 = 44 ohms ... exactly what you need to do the job.