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Morgarella [4.7K]
3 years ago
12

What could people do to DECREASE erosion of the Earth’s surface? A) Cut down more trees. B) Use more land to plant crops. C) All

ow natural vegetation to grow. D) Allow cattle to graze more often.
Physics
2 answers:
Free_Kalibri [48]3 years ago
6 0

What could people do to DECREASE erosion of the Earth’s surface?

  Well, People can plant crops or they can grow plants and if your looking at the options only B and C has that, but lets make sure. So A) "Cut down more trees" does not help DECREASE erosion, if you want to decrease erosion then you have to have roots to make earth's surface stay. A is eliminated, going to B, B says "Use more land to plant crops." that's better because crops have roots so it can keep the surface/land sucked in and will not get erode away. Anyways moving on to C, C "Allow natural vegetation to grow." that kinda helps decrease erosion; so imma keep that in mind, and finally D "Allow cattle to graze more often." does not help at all. So D and A is eliminated, So theres only C and B left, C will kinda help but B will help more; So it will leave us to the final answer which is....

      Answer: B) Use more land to plant crops.

I hope this helps you and I hope you understand what i'm talking about...


From The Special, Idk, my name is weired I just picked this name. I wish I could change it.

Bad White [126]3 years ago
3 0
B) Use more land to plant crops.

By planting crops, the roots can hold ground, thus preventing erosion.
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When the Moon orbits Earth, what is the centripetal force?
nata0808 [166]

Answer:

Gravity is the centripetal force when the moon orbits the earth.

5 0
2 years ago
What type of electromagnetic wave does a light bulb and a radio antenna release?
andrew-mc [135]
I believe that a light bulb releases visible light and a radio antenna releases a radio waves
4 0
3 years ago
(a) what is the acceleration of two falling sky divers (mass 132 kg including parachute) when the upward force of air resistance
Komok [63]

As per the question the mass of two falling sky drivers is 132 kg.

First we have to calculate their acceleration.

Whenever a body falls freely under gravity,its acceleration is acceleration due to gravity i.e g whose value is 9.8 m/s^2.

The earth pulls the object with a force equal to the weight of the body.

Hence the force gravity  F=W= mg   [ here m is mass of the body]

Here m =132 kg.

Hence force of gravity F= mg

                                        =132 kg ×9.8 m/s^2

                                        =1293.6 kg m/s^2

                                         =1293.6 N      [ here N[newton] is the unit of force.]

As per the question the air resistance is one fourth of weight of the bodies.

Hence air resistance F' =1/4 mg

                                       =\frac{1}{4} *1293.6N

                                        =323.4 N

Here F acts in vertically downward direction while F' acts in vertically upward direction.

Hence the net force acting on the particle is F-F'.

                                                 F_{net} =1293.6N -323.4N

                                                         =970.2 N

From Newton's second law of motion we know that net force is the product of mass and acceleration i.e  

                                   F_{net} =ma  [Here a is the acceleration]

                                             a =\frac{F_{net} }{m}

                                                  = \frac{970.2}{132} m/s^2

                                                  =7.35 m/s^2

In the second question it has been told that they descend with uniform speed.hence acceleration of the two bodies will be zero.

 we know that F= ma

                           =m×0

                            =0 N

Hence they will not get any force when they will descend with a uniform speed.


4 0
3 years ago
Two cars having different weights are traveling on a level surface at different constant velocities. Within the same time interv
GuDViN [60]

I think you're saying that once you start pushing on the cars, you want to be able to stop each one in the same time. 

This is sneaky.  At first, I thought it must be both 'c' and 'd'.  But it's not
kinetic energy, for reasons I'm not ambitious enough to go into.
(And besides, there's no great honor awarded around here for explaining
why any given choice is NOT the answer.)

The answer is momentum.

Momentum is (mass x speed).  Change in momentum is (force x time).

No matter the weight (mass) or speed of the car, the one with the greater
momentum is always the one that will require the greater (force x time)
to stop it.  If the time is the same for any car, then more momentum
will always require more force.


4 0
3 years ago
Please help as fast you can
Ilya [14]

Answer:

d a

Explanation:

7 0
3 years ago
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