A navigational beacon in deep space broadcasts at a radio frequency of 50 MHz. A spaceship approaches the beacon with a relative
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Pluto would be placed 39.74 feet far from the Sun.
Astronomers use the gap between Earth and the sun, which is ninety-three million miles, as a new unit of measure called the Astronomical Unit.
Map scale refers to the connection (or ratio) between the space on a map and the corresponding distance on the ground. For example, on a 1:one hundred thousand scale map, 1cm at the map equals 1km on the ground.
The distance between the earth and solar, a = around 150 million km, is defined as one Astronomical Unit (AU). The radius of the solar, the solar is around 700,000 km.
Learn more about Astronomical Unit here brainly.com/question/977568
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When we represent what is given to us on a coordinate plane, we have a figure as shown in the attachment.
To find the distance between P and R, we have to find the Net Displacement of the ship (brown arrow in the figure).
For that, we use the rules for Vector addition.
We see that the first displacement = 30 km (blue arrow) is along the y-axis, but the second part of the ship's journey
= 20 km (red arrow) is at an angle with reference to y-axis.
So, we first find the components of the red arrow along X and Y.
Component of along X-axis is given by
= 10 km
Component of along Y-axis is given by
= 17.32 km
We now add all the vectors along X and along Y separately.
Net Displacement along X
Net Displacement along Y = 47.32 km
Now that we have the components of the net displacement along X and Y, we make use of Pythagorean Theorem to calculate the
Therefore, [tex]D_{net} = 48.37 km.
Hence, the distance between the ports P and R is 48 km.
