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polet [3.4K]
3 years ago
9

Write the number in scientific notation. 6. 0.00000625

Mathematics
1 answer:
ycow [4]3 years ago
6 0

6.25x 10^-6

thats the answer

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azamat
Does the rate of change equal for each.
take the output difference and divide by the input distance
1st -5/10 = -1/2
2nd -1/2
3rd -5/10.= -1/2
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Natalia paid $38.95 for three medium-sized pizzas and a salad. Solve an equation to find the cost of one pizza,p, if Natalia pai
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Suppose you pay $1.00 to roll a fair die with the understanding you will get $3.00 back rolling a 4 or a 2, and nothing otherwis
nikdorinn [45]

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Every 6 rolls you are expected to win $6

Every 3 rolls you are expected to win $3.

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3 years ago
What value has a z-score of -0.67, if the mean is 18 and the standard deviation is 1.68?
uranmaximum [27]
The data point is 1.6 standard deviations above the mean.
Step-by-step explanation:
Z-score
It is the number of standard deviations from the mean that a data point is. It's a measure of how many standard deviations below or above the population mean a raw score is.
A Z-score is also known as a standard score and it can be placed on a normal distribution curve.
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7 0
3 years ago
The atmospheric pressure P on a balloon or in aircraft decreases with increasing height . This pressure measured in Millimeters
Vesnalui [34]

Answer:

(A)   5.47 km

(B)   1.38 km

Step-by-step explanation:

The relationship between Pressure (mmHg) and Height (km) is given by the equation below:

p =760 e⁻ 0.145h----------------------------------------------------- (1)

(a) The height of the aircraft can be calculated by making 'h' the subject of equation (1)

In (p/760) = -0.145 h

h = -In (p/760) /0.145

h= In (760/p)/ 0.145------------------------------------------------- (2)

For the aircraft, p =344 mmHg; substituting into (2)

h = In (760/344)/0.145

   = 0.7926/0.145

   = 5.4662 km

   ≈ 5.47 km

(b) p= 622 mmHg at the mountain top. Substituting into equation  (2) we have:

h = In (760/622)/0.145

  = 0.2003 / 0.145

  =  1.3813 km

  ≈  1.38 km

4 0
3 years ago
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