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Answer:</h2>
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Step-by-step explanation:</h2>
For a better understanding of this problem, see the figure below. Our goal is to find 
. Since:
and is a common side both for ΔMRN and ΔMQN, then by SAS postulate, these two triangles are congruent and:
By Pythagorean theorem, for triangle NQP:
Applying Pythagorean theorem again, but for triangle MQN:
Surface area of the cylinder is 294π in².
Step-by-step explanation:
- Step 1: Surface area of a cylinder = 2πrh + 2πr² Here, r = 7 in, h = 14 in
⇒ Surface Area = 2 × π × 7 × 14 + 2 × π × 7 × 7
= π (196 + 98) = 294π in²
6 sin 2x = 6 cos x Using the identity sin 2x = 2 sin x cos x:-
12 sin x cos x = 6 cos x
6 cos x ( 2 sin x - 1) = 0
either 6 cos x = 0 or 2 sin x - 1 = 0 so sin x = 1/2
x = pi/2, 3pi/2 , pi/6, 5pi / 6
answer is ( pi/6, pi/2, 5pi/6, 2pi/2)
Get the value of the decimal:
Remember that percentages are simply the value of a decimal multiplied by 100. (From the Latin, "per centus", meaning "per 100")
therefore:
