Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
Hey there!
Let's look at the squares of all of our answer options. We will compare them to eighty two to see which it belongs in.
A. 36 and 49.
B. 49 and 64.
C. 64 and 81.
D. 81 and 100
As you can see, 82 is in between 81 and 100, so the answer is D. 9 and 10.
Also, the square root of 82 is about 9.05, and this fits our answer.
Have a wonderful day!
The answer is < :) hope this helped
<span>.. P(at least 2 of 3 baskets)
= P(2 of 3 baskets) + P(3 of 3 baskets)
= (basket)(basket)(no basket) + (basket)(no basket)(basket) + (no basket)(basket)(basket) + (basket)(basket)(basket)
= (0.8)(0.8)(0.2) + (0.8)(0.2)(0.8) + (0.2)(0.8)(0.8) + (0.8)(0.8)(0.8)
= 3(0.8)(0.8)(0.2) + 0.8^3
= 0.384 + 0.512
= 0.896
QED.</span><span>
</span>
